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3 years ago

. Please help Add or subtract.

Mathematics

2 answers:

telo118 [61]3 years ago

4 0

Answer:

Lt is very easy answer u can't

GrogVix [38]3 years ago

3 0

Answer:

$\frac{1}{x-6}$

Step-by-step explanation:

$\frac{x}{x^2-2x-24}-\frac{-4}{x^2-2x-24}\\\\\frac{x-(-4)}{x^2-2x-24}\\\\\frac{x+4}{(x+4)(x-6)}\\\\\frac{1}{x-6}$

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Alguien sabe hacer esta operación a travez de la sustitución:<br> 3y=2<br> 3x-y=2

blsea [12.9K]

Try to use y=Mx+b and if that doesn’t help just say so and I will help even more

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3 years ago

PLEASE I NEED HELP INSTANTLY <br> I WILL GIVE BRAINLY AND THANKS

Goryan [66]

Answer:

so you're going to need to find the slope. in order to do that use (y2-y1)/(x2-x1)

(7-(-2))/(0-8)

simplify

9/-8

simplify -9/8

now using y=mx+b, we need to find b. so we can plug in the coordinates of (0,7) or (8,-2). let's use (8,-2) because it involves more math.

y=mx+b

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multiply (-9/8) by 8 to get -9

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add 9 to both sides

7=b

so our equation is now

y=-(9/8)x+7

Step-by-step explanation:

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2 years ago

Read 2 more answers

Which ratios have a unit rate less than 1? choose all that apply.

DaniilM [7]

Answer:

2apply.

Step-by-step explanation:

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2 years ago

What is the answer to 18 divided by parentheses 5-2 parentheses

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3 years ago

Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real

garik1379 [7]

The complete question is

"Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real number solutions? (The related quadratic function will have two x-intercepts.) Check all that apply.

0 = 2x^2 – 7x – 9

0 = 4x^ 2 – 3x – 1

The quadratic equations that have real number solutions are; 4x^2 – 3x – 1, and 2x^2 – 7x – 9.

<h3>What is the formula for Discriminant?</h3>

The formula for finding the discriminant is

$b^2 - 4ac$

The solution contains the term $\sqrt{b^2 - 4ac}$ which will be:

Real and distinct if the discriminant is positive

Real and equal if the discriminant is 0

Non-real and distinct roots if the discriminant is negative

For the quadratic equation $2x^2 - 7x - 9$

$b^2 - 4ac$

$= (-7) ^2 - 4( 2) ( -9)\\\\= 49 + 72 = 121$

This equation has two real number solutions.

For the quadratic equation $4x^ 2 - 3x- 1$

$b^2 - 4ac$

$= (-3) ^2 - 4( 4) ( -1)\\\\= 9 + 16 = 25$

This equation will have two real number solutions.

Learn more on discriminant here:

brainly.com/question/1537997

#SPJ1

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2 years ago