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2 years ago

Solve x^3 = 1 over 8. 1 over 2 ±1 over 2 1 over 4 ±1 over 4

Mathematics

2 answers:

lara [203]2 years ago

8 0

x³ = 1/8

8 can be written as 2³

x³ = 1/2³

(x)³ = (1/2)³

When exponents are same bases are taken and exponents are eliminated

x = 1/2

<u>Hence, the required answer is 1/2</u>

Oduvanchick [21]2 years ago

7 0

Answer:

x = 1/2

Step-by-step explanation:

x^3 = 1/8

Take the cube root of each side

x^3 ^ (1/3) = (1/8)^ (1/3)

Rewriting 8 as 2^3

x^3 ^ (1/3) = (1/2^3)^ (1/3)

x = 1/2

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2 years ago

Out of 250 coins, 50 are in mint condition. What is the ratio of mint condition coins to the total number of coins?

dimulka [17.4K]

<u>Answer:</u>

$1 : 5$

<u>Step-by-step explanation:</u>

Given:

Mint condition coins = $50$

Total number of coins = $250$

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The questions asks for the ratio between mint condition coins to the total number of coins, so:

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2 years ago

A.What is the slope

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2 years ago

What is the surface area of the figure? Use 3.14 for π.

fredd [130]

Answer:

Option 3

Step-by-step explanation:

We want to work out the surface-area

This is a cylinder and the formula for the surface area of a cylinder is :

2πrh+2πr^2

^ means to the power of

The radius is 15

The length is 18

2(3.14)(15)(18) + 2(3.14){15}^2

Part 1:

(6.28)(15)(18)

(6.28)(270)

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Part 2:

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15^2 = 225

(6.28)(225)

1413

Part 3:

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6 0

2 years ago

Read 2 more answers

Could you help plz.

I am Lyosha [343]

Cost of each bags of flour = $2.50

Cost of each bags of butter = $3.75

Solution:

Let f be the bags of flour and b be the pounds of butter.

Cost of 20 bags of flour 16 pound of butter = 110

⇒ 20f + 16b = 110 -------------------- (1)

Cost of 30 bags of flour 12 pound of butter = 120

⇒ 30f + 12b = 120 -------------------- (2)

Equation (1) and (2) are the system of equations.

(2) ⇒ 30f + 12b = 120

Subtract 30f from both sides.

⇒ 12b = 120 – 30f

Divide by 12 on both sides.

$$\Rightarrow b =\frac{120-30f}{12}$ -------------------- (3)

Substitute (3) in (1).

$$20f+16\left(\frac{120-30f}{12}\right)=110$

$$20f+4\left(\frac{120-30f}{3}\right)=110$

$$20f+4(40-10f)=110$

$$20f+160-40f=110$

Subtract 160 from both sides.

$$-20f=-50$

Divide by –20, we get

$$f=\frac{5}{2}$

f = 2.50

Substitute f = 2.5 in equation (3), we get

$$\Rightarrow b =\frac{120-30(2.50)}{12}$

$$b=\frac{15}{4}$

b = 3.75

Cost of each bags of flour = $2.50

Cost of each bags of butter = $3.75

7 0

3 years ago