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trapecia [35]
3 years ago
6

Solve x^3 = 1 over 8. 1 over 2 ±1 over 2 1 over 4 ±1 over 4

Mathematics
2 answers:
lara [203]3 years ago
8 0
<h3>A N S W E R :</h3>

x³ = 1/8

8 can be written as 2³

x³ = 1/2³

(x)³ = (1/2)³

When exponents are same bases are taken and exponents are eliminated

x = 1/2

  • <u>Hence, the required answer is 1/2</u>

Oduvanchick [21]3 years ago
7 0

Answer:

x = 1/2

Step-by-step explanation:

x^3 = 1/8

Take the cube root of each side

x^3 ^ (1/3) = (1/8)^ (1/3)

Rewriting 8 as 2^3

x^3 ^ (1/3) = (1/2^3)^ (1/3)

x = 1/2

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Step-by-step explanation:

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3 years ago
The proof that AMNS AQNS is shown.
FrozenT [24]

Answer:

The answer is "MS and QS".

Step-by-step explanation:

Given ΔMNQ is isosceles with base MQ, and NR and MQ bisect each other at S. we have to prove that ΔMNS ≅ ΔQNS.

As NR and MQ bisect each other at S

⇒ segments MS and SQ are therefore congruent by the definition of bisector i.e   MS=SQ

In ΔMNS and ΔQNS

MN=QN       (∵ MNQ is isosceles triangle)

∠NMS=∠NQS     (∵ MNQ is isosceles triangle)

MS=SQ         (Given)

By SAS rule, ΔMNS ≅ ΔQNS.

Hence, segments MS and SQ are therefore congruent by the definition of bisector.

The correct option is MS and QS

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3 years ago
Jocelyn and her children went into a bakery and she bought $9 worth of cookies and brownies. Each cookie costs $0.50 and each br
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Jace bought 4 cookies and 2 brownies from the bakery.

Let x represent the number of cookies and y represent the number of brownies.

Since he bought $9 worth of cookies and brownies. Each cookie costs $0.75 and each brownie costs $3. hence:

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Also, he bought twice as many cookies as brownies, hence:

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Solving equation 1 and 2 simultaneously gives x = 4, y = 2

Hence Jace bought 4 cookies and 2 brownies from the bakery.

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3 years ago
Robert works in a toll booth. About 18 to 23 cars pass through Robert's booth every 23 minutes. Which is a reasonable estimate f
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3 years ago
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