Answer:

Step-by-step explanation:
Let <em>A</em> be the event of getting an odd number.
<em>P(A)</em> be the probability of getting an odd number.
Total odd numbers here are 6 i.e. 
Here, total numbers in the game are 12 i.e
.
Formula for probability of an <em>event E</em> can be observed as:


Let <em>B</em> be the event of getting 11.
<em>P(B)</em> be the probability of getting 11.
Total number of possible cases is 1.

is the probability that we get 11 and an odd number.
Possible number of cases = 1

<em>P(B/A)</em> is the probability that we get an 11 given that it is an odd number.

Hence, P(B/A) = 
Answer:
Ask yourself: "Can I roll a prime number and an odd number at the same time?"
Since the answer is "yes it is possible" (eg: rolling a 3), this means the two events are not mutually exclusive. Mutually exclusive events have nothing in common.
In terms of a venn diagram, mutually exclusive events have no overlapping shared region.Step-by-step explanation:
Answer:
6+3x=w
Step-by-step explanation:
6 *more* more always means +
and then three *times* times always means *
so it would equal 6+3x=w
Answer:
1. 
2. ![(p^2-6)[1-q(p^2-6)]](https://tex.z-dn.net/?f=%28p%5E2-6%29%5B1-q%28p%5E2-6%29%5D)
Step-by-step explanation:
1. The first thing to do to factor the expression is to take the expression (a + 3) as a common factor with its lowest exponent.
Then the expression.
remains as:

2. The first thing to do to factor the expression is to take the expression
as its common factor with its lowest exponent.
Then the expression
remains as:
![(p^2-6)[1-q (p^2-6)]](https://tex.z-dn.net/?f=%28p%5E2-6%29%5B1-q%20%28p%5E2-6%29%5D)