Answer:
‹A = 141°
‹B = 28°
‹C = 11°
*These angles are rounded to the nearest whole*
Step-by-step explanation:
Because you are only given sides you can find an individual angle measures with the inverse law of cosines.
Remember the side opposite of the angle corresponds to that angle.
a² = b² + c² - 2bc cos(A) →
A = cos⁻¹ (a² - b² - c² / -2bc)
b² = a² + c² - 2ac cos(B) →
B = cos⁻¹ (b² - a² - c² / -2ac)
c² = a² + b² - 2ab cos(C) →
C = cos⁻¹ (c² - a² - b² / -2ab)
AE Should be Craig answer
Answer:
The answer in the procedure
Step-by-step explanation:
Let
A1 ------> the area of the first square painting
A2 ----> the area of the second square painting
D -----> the difference of the areas
we have


case 1) The area of the second square painting is greater than the area of the first square painting
The difference of the area of the paintings is equal to subtract the area of the first square painting from the area of the second square painting
D=A2-A1


case 2) The area of the first square painting is greater than the area of the second square painting
The difference of the area of the paintings is equal to subtract the area of the second square painting from the area of the first square painting
D=A1-A2


I don't know 1 but 2 can be 2.3 over 4.5 I think sorry if it's wrong but I hope it helps