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stepan [7]
3 years ago
7

F(x)=x^3-2x^2-x what is f(-4)

Mathematics
1 answer:
steposvetlana [31]3 years ago
5 0

Answer:

gdhjdjdjjdjudjdhhdjdhjdjjdjfhhd

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5*10^5 is how many times bigger that 1*10^5
weqwewe [10]

Answer:

5

Step-by-step explanation:

5*10^5=500000 and 1*10^5=100000

6 0
2 years ago
9x + 9 + 2x - 7(3 + x) =
SashulF [63]

Answer:

4x-12 or 4(x-3)

Step-by-step explanation:

9x+9+2x-7(3+x)

9x+2x+9-21-7x

11x-12-7x

11x-7x-12

4x-12

4 0
3 years ago
You start a lawn care company with four friends. You agree to split the profits equally. The tools you need to buy cost $525. Ho
rosijanka [135]
100$ because the income you have to earn is 400$, right? If so then 100 * 4 give you 400.
4 0
2 years ago
Read 2 more answers
Help geometry what I m jlf <br> Picture provided
Zolol [24]

Answer:

\angle\,JLF = 114^o  which agrees with option"B" of the possible answers listed

Step-by-step explanation:

Notice that in order to solve this problem  (find angle JLF) , we need to find the value of the angle defined by JLG and subtract it from 180^o, since they are supplementary angles. So we focus on such, and start by drawing the radii that connects the center of the circle (point "O") to points G and H, in order to observe the central angles that are given to us as 90^o and 138^o. (see attached image)

We put our efforts into solving the right angle triangle denoted with green borders.

Notice as well, that the triangle JOH that is formed with the two radii and the segment that joins point J to point G, is an isosceles triangle, and therefore the two angles opposite to these equal radius sides, must be equal. We see that angle JOH can be calculated by : 360^o-90^o-138^o=132^o

Therefore, the two equal acute angles in the triangle JOH should add to:

180^o-132^o=48^o resulting then in each small acute angle of measure 24^o.

Now referring to the green sided right angle triangle we can find find angle JLG, using: 180^o-24^o-90^o=66^o

Finally, the requested measure of angle JLF is obtained via: 180^o-66^o=114^o

4 0
3 years ago
If f(x) = x2 – 1 and g(x) = 2x – 3, what is the domain
Ainat [17]
Begin by finding the lowest point the quadratic equation can be, the vertex; 

x²-1= is just a translation down of the graph x²

vertex; (0, -1) and since the graph of x² would extend to infinity beyond that point, we can say {x| x≥0} for domain and {y| y≥-1}. 

For the linear equation, it is possible to have all x and y values, therefore range and domain belong to all real numbers. 

Hope I helped :) 
5 0
3 years ago
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