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Stells [14]
3 years ago
11

Plz help plz plz only 4 question​

Mathematics
1 answer:
soldi70 [24.7K]3 years ago
8 0

c.

x = 130° (exterior opposite angles)

y + x = 180° (linear pair of angles)

=> y + 130° = 180°

=> y = 180° - 130°

=> y = 50°

d.

z = 100° (corresponding angles)

a = 100° (corresponding angles)

x + 100° = 180° (linear pair of angles)

=> x = 180° - 100°

=> x = 80°

y = x (interior opposite angles)

=> y = 80°

b = y (corresponding angles)

=> b = 80°

g.

a = 112° (vertically opposite angles)

b = a (interior opposite angles)

=> b = 112°

x = 78° (vertically opposite angles)

x + y = 180° (interior angles on the same side of transversal)

=> 78° + y = 180°

=> y = 180° - 78°

=> y = 102°

h.

f = 120° (vertically opposite angles)

e = 105° (vertically opposite angles)

c = 120° (corresponding angles)

d = 105° (corresponding angles)

a + d = 180° (linear pair of angles)

=> a + 105° = 180°

=> a = 180° - 105°

=> a = 75°

b + c = 180° (linear pair of angles)

=> b + 120° = 180°

=> b = 180° - 120°

=> b = 60°

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C

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Drag the tiles to the correct boxes to complete the pairs not all tiles will be used match each quadratic graph to its respectiv
ch4aika [34]

Answer:

Part 1) The function of the First graph is f(x)=(x-3)(x+1)

Part 2) The function of the Second graph is f(x)=-2(x-1)(x+3)

Part 3) The function of the Third graph is f(x)=0.5(x-6)(x+2)

See the attached figure

Step-by-step explanation:

we know that

The quadratic equation in factored form is equal to

f(x)=a(x-c)(x-d)

where

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c and d are the roots or zeros of the function

Part 1) First graph

we know that

The solutions or zeros of the first graph are

x=-1 and x=3

The parabola open up, so the leading coefficient a is positive

The function is equal to

f(x)=a(x-3)(x+1)

Find the value of the coefficient a

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therefore

The function is equal to

f(x)=(x-3)(x+1)

Part 2) Second graph

we know that

The solutions or zeros of the first graph are

x=-3 and x=1

The parabola open down, so the leading coefficient a is negative

The function is equal to

f(x)=a(x-1)(x+3)

Find the value of the coefficient a

The vertex is equal to the point (-1,8)

substitute and solve for a

8=a(-1-1)(-1+3)

8=a(-2)(2)

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therefore

The function is equal to

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Part 3) Third graph

we know that

The solutions or zeros of the first graph are

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The parabola open up, so the leading coefficient a is positive

The function is equal to

f(x)=a(x-6)(x+2)

Find the value of the coefficient a

The vertex is equal to the point (2,-8)

substitute and solve for a

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3 0
4 years ago
Help meeeeeeeeeeeeeee!!!!!!​
koban [17]

Answer:

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3w=15

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7w=0

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your welcome

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3 years ago
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