Please please I need help ((((riiiight now))) What's the right answer and explain why!!!!!

Mathematics

2 answers:

tensa zangetsu [6.8K]2 years ago

7 0

It’s the first one because it’s the just the right bae I just seen his i might be right idk knoww

Ilia_Sergeevich [38]2 years ago

5 0

First you can apply the a²-b² = (a+b)(a-b) theorem, you'll get:

(p²)² - 9² = (p²+9)(p²-9), but that's not all, you can apply it again on the last factor:

(p²+9)(p²-3²) = (p²+9)(p+3)(p-3)

The first factor cannot be simplified like that, so that's the furthest factorization. So answer (3) is the right one.

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G(x) = -2x^3 – 15x^2 + 36x

shusha [124]

Consider the function $G(x) = -2x^3 - 15x^2 + 36x.$ First, factor it:

$G(x) = -2x^3 - 15x^2 + 36x=-x(2x^2+15x-36)=\\ \\=-x\cdot 2\cdot \left(x-\dfrac{-15-\sqrt{513}}{4}\right)\cdot \left(x-\dfrac{-15+\sqrt{513}}{4}\right).$

The x-intercepts are at points $\left(\dfrac{-15-\sqrt{513} }{4},0\right),\ (0,0),\ \left(\dfrac{-15+\sqrt{513} }{4},0\right).$

1. From the attached graph you can see that

function is positive for $x\in \left(-\infrty, \dfrac{-15-\sqrt{513} }{4}\right)\cup \left(0,\dfrac{-15+\sqrt{513} }{4}\right);$
function is negative for $x\in \left(\dfrac{-15-\sqrt{513} }{4},0\right)\cup \left(\dfrac{-15+\sqrt{513} }{4},\infty\right).$