K(x) = (1/2)ˣ
Since a (=1/2) is < 1, this exponential function is decreasing .
y-intercept for x = 0
k(x) =(1/2)⁰ → k(x) =1, then y-intercept = 1
Horizontal Asymptote:
lim k(x) = (1/2)ˣ = 0
x→∞
Horizontal asymptote x = 0
Answer:
The largest integer is 29.
Step-by-step explanation:
Let the consecutive positive integers are x, x+1 and x+2.
The square of sum of squares of three consecutive positive integers is 2354 such that,

It is a quadratic equation whose solution is given by :
x = 27 and x = -29
First positive integer = 27
Second positive integer = 27+1 = 28
Third positive integer = 27+2 = 29
Hence, the largest integer is 29.
5×3=15 because 5 plus five plus five equals 15 if you add it together correctly
Let x ft be the lenght of the fence and y ft be the width of the fence.
1. The length of the habitat should be at least 80 feet, then

2. The perimeter of the habitat should be no more than 300 feet. The perimeter of the fenceis 2x+2y ft, then

3. The system of inequalities that represent the model is

The graph of these inequalities is attached.
Two possible solutions are
- x=100 ft, y=20 ft (100≥80 and 2·100+2·20=240≤300);
- x=110 ft, y=30 ft (110≥80 and 2·110+2·30=280≤300).