How many 3-digit numerical passwords are there if a digit cannot be repeated?
1 answer:
The first digit of the password can be any of the ten digits - 10 possibilities.
A digit cannot be repeated, so the second digit can be any digit except the one you chose for the first digit - 9 possibilities.
The third digit can be any digit except the digits you chose for the first and second digit - 8 possibilities.
Using the rule of product:
There are 720 passwords.
A digit cannot be repeated, so the second digit can be any digit except the one you chose for the first digit - 9 possibilities.
The third digit can be any digit except the digits you chose for the first and second digit - 8 possibilities.
Using the rule of product:
There are 720 passwords.
You might be interested in
Answer:
a) BD = 5
b) FD = 13
Step-by-step explanation:
For both questions we follow pythagoras therom.
For the first one we do 3^2 +4^2 = 25 and then we root this answer to 5
For the second we have to find the base of GD in order to find FD. GD will be 4^2+12^2 which equals to 160 and then you root.
Finally, we can find FD which is sqaure root of 160^2 + 3^2 = 169. The square root of 169 is 13. Answer is 13.
Answer:
188km
Hi there!!
I hope this answer helps.
Step-by-step explanation:
You can solve this with simple cross multiplication. (proportion)
Step-by-step explanation:
