3 years ago

If the equation of the line is y=12x-7 what is slope and y intercept

Mathematics

1 answer:

frez [133]3 years ago

6 0

Answer: Slope=12 y-intercept= (0,-7)

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NEED ANSWERED NOW

hammer [34]

x = 3,-1, multiplicity of 2.

Therefore, it is 4-degree polynomials. (considering that x = 3,-1,2,2)

We just convert these x-values into x-intercept form and convert again in standard form by multiplying.

(x-3)(x+1)(x-2)²

(x²-2x-3)(x²-4x+4)

(x⁴-4x³+4x²-2x³+8x²-8x-3x²+12x-12)

Thus the answer is x⁴-6x³+9x²+4x-12

7 0

3 years ago

Quadrilateral JKLM has vertices J(-4,-1), K(-1,2), L(6,2). For what coordinates of point M is JKLM a parallelogram?

Burka [1]

Answer: B

Look At the pictures Please. :)

I graphed your points so you can see it visually. Look through all the pictures they show my process.

7 0

3 years ago

A) 90 clockwise

nydimaria [60]

Answer:

A.) 90 clockwise

E.)270 Counter Clockwise

Step-by-step explanation:

A.) Ro, -90 Rotation about the origin (0,0) 90° clockwise

(x, y) ⇒ (y, -x)

(-1, 5) ⇒ (5, 1)

E.) Ro, 270 Counter Clockwise

(x, y) ⇒ (y, -x)

(-1, 5) ⇒ (5, 1)

6 0

3 years ago

Establish the identity.<br> (2 cos 0-6 sin 0)² + (6 cos 0+2 sin 0)2 = 40

kogti [31]

Rewriting the left-hand side as follows,

$(2\cos\theta-6\sin \theta)^2 +(6\cos \theta+2\sin \theta)^2\\\\=4\cos^2 \theta-24\cos \theta \sin \theta+36 \sin^2 \theta+36 \cos^2 \theta+24 \cos \theta \sin \theta+4 \sin^2 \theta\\\\=40\cos^2 \theta+40 \sin^2 \theta\\\\=40(\cos^2 \theta+\sin^2 \theta)\\\\=40$