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Charra [1.4K]
3 years ago
13

Help me please

Mathematics
1 answer:
kari74 [83]3 years ago
6 0

Answer:

\frac{ \cos(80) }{ \sin(10) }  +  \frac{ \sin(20) }{ \cos(70) }  = 2 \\  \frac{ \cos(90 - 10) }{ \sin(10) }  +  \frac{ \sin(20) }{ \cos(9 0 - 20) }  = 2 \\  \frac{ \sin(10) }{ \sin(10) }  +  \frac{ \sin(20) }{ \sin(20) }  = 2 \\ 1 + 1 = 2 \\ 2 = 2 \\  \\  \frac{ \cot(40) }{ \tan(50) }  +  \frac{ \cos(65) }{ \sin(115) }  = 2 \\  \frac{ \cot(90 - 50) }{ \tan(50) }  +  \frac{ \cos(65) }{ \sin(90 + 65) }  = 2 \\  \frac{ \tan(50) }{ \tan(50) }  +  \frac{ \cos(65) }{ \cos(65) }  = 2 \\ 1 + 1 \\  = 2

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