Answer:
θ = 2 π n_1 + π/2 for n_1 element Z or θ = 2 π n_2 for n_2 element Z
Step-by-step explanation:
Solve for θ:
cos(θ) + sin(θ) = 1
cos(θ) + sin(θ) = sqrt(2) (cos(θ)/sqrt(2) + sin(θ)/sqrt(2)) = sqrt(2) (sin(π/4) cos(θ) + cos(π/4) sin(θ)) = sqrt(2) sin(θ + π/4):
sqrt(2) sin(θ + π/4) = 1
Divide both sides by sqrt(2):
sin(θ + π/4) = 1/sqrt(2)
Take the inverse sine of both sides:
θ + π/4 = 2 π n_1 + (3 π)/4 for n_1 element Z
or θ + π/4 = 2 π n_2 + π/4 for n_2 element Z
Subtract π/4 from both sides:
θ = 2 π n_1 + π/2 for n_1 element Z
or θ + π/4 = 2 π n_2 + π/4 for n_2 element Z
Subtract π/4 from both sides:
Answer: θ = 2 π n_1 + π/2 for n_1 element Z
or θ = 2 π n_2 for n_2 element Z
12 mins
60 mins per hour
we are trying to find an equivilent fraction that has 60 in the bottom
so
(5 and 1/2)/12=x/60
multiply both sides by 60
330/12=x
divide
27 and 1/2=x
she read 27.5 pages per minute
Answer:
Step-by-step explanation:
9x⁴ – 2x² – 7 = 0
Let's say that u = x²:
9u² – 2u – 7 = 0
Factor:
(u – 1) (9u + 7) = 0
u = 1, -7/9
Since u = x²:
x² = 1, -7/9
x = ±1, ±i √(7/9)
Answer:
2.947
2.946
2.948
2.949
2.945
Step-by-step explanation:
all decimal points are 5 or greater so you round up.