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Evgen [1.6K]
3 years ago
15

Whats 1+1? In numberal form of fashion?

Mathematics
2 answers:
meriva3 years ago
6 0
The answer to your question is ll
Eduardwww [97]3 years ago
5 0

Answer:

I + I = II is the answer.

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Multiply.
Salsk061 [2.6K]

Answer:

B. 2.25×10−^17

Step-by-step explanation:

3 0
3 years ago
Let R be a system consisting of rational expressions. Which operations are closed under R
Alex_Xolod [135]

We say that a set of numbers is <em>closed</em> under an operation when, no matter which two numbers we pick to use it on, we always end up with another number in the set.

The <em>natural numbers</em>, the positive whole numbers, are the first kind you ever learn about - 1, 2, 3, 4, 5, 6, etc. We say that the natural numbers are <em>closed under addition</em> because the <em>sum </em>of any two natural numbers is another natural number (e.g. 2 + 3 = 5, 67 + 52 = 109, etc.) We can also say that they're closed under multiplication, since the <em>product </em>of any two of them gives us another natural number (2 x 3 = 6, 10 x 7 = 70, 54 x 65 = 3510).

The natural numbers are <em>not </em>closed under subtraction, though, since problems like 3 - 5 = ? have no natural number solutions. We have to extend our number system to the <em>integers</em>, the set of all positive and negative whole numbers including 0, to make that solution possible, and we can then find that 3 - 5 = -2, an integer. We can now say that <em>the integers are closed under addition, subtraction, and multiplication</em>.

There are still situations we can't handle with just the integers, though. 3 ÷ 5 = ? has no solution in the integers since the solution isn't a whole number. To fix this, we extend our system again and finally reach the rational numbers, numbers written as ratios between integers (1/2, 3/6, -7/10, etc.) We can now add, subtract, multiply, and divide any two rational numbers and end up with another rational number, so we can say addition, subtraction, multiplication, and division are closed under R.

5 0
4 years ago
Read 2 more answers
For the function f(x) = 4x^3 -36x^2 + 5: (a) find the critical numbers, (b) find the open intervals where the function is increa
Nataly_w [17]

\bf f(x)=4x^3-36x^2+5\implies \cfrac{df}{dx}=12x^2-72x\implies \stackrel{\textit{setting the derivative to 0}}{0=12x(x-6)} \\\\\\ x= \begin{cases} 0\\ 6 \end{cases}


so we have those critical values, which gives us the intervals of (-∞, 0] , [0, 6] and [6, +∞).

where is it increasing or decreasing?  well, that's just a matter of checking a value on each region for the the first derivative, namely the first derivative test.

we can check for f(-1) = 12(-1)² - 72(-1),  is a positive value, increasing.

and check f(1) = 12(1)² - 72(1), is a negative value, decreasing.

and check f(7) = 12(7)² - 72(7), positive, so increasing.

check the picture below, and you can see there which are the minima or maxima.

3 0
3 years ago
Im bored someone interact with me lol
lana66690 [7]

Answer:

oki wsp

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Solve this equation 3x4x4x15-14+1= ?
Deffense [45]

Answer:

my answer is 707

Step-by-step explanation:

i used a calculator lol

6 0
3 years ago
Read 2 more answers
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