Answer:
right angles and obtuse angles
Step-by-step explanation:
We assume that anything that <em>looks like</em> a right angle <em>is</em> a right angle.
The angles at the left end of each horizontal line are right angles.
The angles at the right end of each horizontal line are obtuse angles.
The angle where the diagonal lines meet is a right angle.
The shape contains right angles and obtuse angles.
So you need to come up with a perfect square that works for the x coefficients.
like.. (2x + 2)^2
(2x+2)(2x+2) = 4x^2 + 8x + 4
Compare this to the equation given. Our perfect square has +4 instead of +23. The difference is: 23 - 4 = 19
I'm going to assume the given equation equals zero..
So, If we add subtract 19 from both sides of the equation we get the perfect square.
4x^2 + 8x + 23 - 19 = 0 - 19
4x^2 + 8x + 4 = - 19
complete the square and move 19 over..
(2x+2)^2 + 19 = 0
factor the 2 out becomes 2^2 = 4
ANSWER: 4(x+1)^2 + 19 = 0
for a short cut, the standard equation
ax^2 + bx + c = 0 becomes a(x - h)^2 + k = 0
Where "a, b, c" are the same and ..
h = -b/(2a)
k = c - b^2/(4a)
Vertex = (h, k)
this will be a minimum point when "a" is positive upward facing parabola and a maximum point when "a" is negative downward facing parabola.
Answer:
(-3, 0), (0, -9)
Step-by-step explanation:
x-intercept: Let y = 0 and find x: 0 = -3x - 9), or 3x = -9. Then x = -3, and the x-intercept is (-3, 0).
y-intercept. Let x = 0 and find y. y = -3(0) - 9 = -9. The y-intercept is (0, -9).
Answer:
y=0
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
2.6y-4/15y+7/6y=7/3y
2.6y-(-)4/15y+7/6y=7/3y
(2.6y-4/15y+7/6y)=7/3y (combine like terms)
7/2y = 7/3y
Step 2: Subtract 7/3y from both sides.
7/2y - 7/3y = 7/3y - 7/3y
7/6y = 0
Step 3: Multiply both sides by 6/7
6/7 . 7/6y = 6/7 . 0
y = 0
