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Sonja [21]
3 years ago
9

RS is the segment bisector. If OQ = 32 and PO = 4x,

Mathematics
1 answer:
labwork [276]3 years ago
8 0

Answer:

8

Step-by-step explanation:

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Lella will rent a car for the weekend. She can choose one of two plans. The first plan has an initial fee of $46 and costs an ad
Helen [10]
The plans cost the same at 125 miles. the cost is $63.50
6 0
3 years ago
A floor plan shows that a tiny house has a length of 40 feet and a width of 25 feet
Oduvanchick [21]

Answer:

1000 square feet.

Step-by-step explanation:

to find the area, you multiply the length by the width

40*25=1000

3 0
2 years ago
Write 16 + 32 = as a product of two factors using GCF and the distributive property
N76 [4]

Answer:

16 (1+2)

Step-by-step explanation:

factors of 16: 1,2,4,8,16

factors of 32: 1,2,4,8,16,32

16 x 1 = 16

16 x 2 = 32

8 0
3 years ago
Find g'​(t) for the function ​g(t) = 7/t^4
Alex17521 [72]

The differentiation of the function g(t) = 7/t⁴ will be equal to g¹(t)=-28/t⁵

<h3>What is differentiation?</h3>

The method of determining the derivative, or rate of change, of a function in mathematics.is termed as the differentiation.

Given that:-

g(t)= \dfrac{7}{t^4}

The derivative will be calculated as:-

g'(t)=7   \dfrac{d}{dt}(t^{-4})\\\\\\g'(t)=7\times (-4t^{-5})\\\\\\g'(t)=\dfrac{-28}{t^5}

Therefore the differentiation of the function g(t) = 7/t⁴ will be equal to g¹(t)=-28/t⁵

To know more about derivatives follow

brainly.com/question/954654

#SPJ1

3 0
2 years ago
Assume the readings on thermometers are normally distributed with a mean of 0 degrees C and a standard deviation of 1.00 degrees
lozanna [386]

Answer: 0.0035

Step-by-step explanation:

Given : The readings on thermometers are normally distributed with a mean of 0 degrees C and a standard deviation of 1.00 degrees C.

i.e.  \mu=0 and \sigma= 1  

Let x denotes the readings on thermometers.

Then, the probability that a randomly selected thermometer reads greater than 2.17 will be :_

P(X>2.7)=1-P(\xleq2.7)\\\\=1-P(\dfrac{x-\mu}{\sigma}\leq\dfrac{2.7-0}{1})\\\\=1-P(z\leq2.7)\ \ [\because\ z=\dfrac{x-\mu}{\sigma}]\\\\=1-0.9965\ \ [\text{By z-table}]\ \\\\=0.0035

Hence, the probability that a randomly selected thermometer reads greater than 2.17 = 0.0035

The required region is attached below .

8 0
3 years ago
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