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3 years ago

If f(x) = 4 – x2 and g(x) = 6x, which expression is equivalent to (g – f)(3)?

1 answer:

5 0

F(x) = -x² + 4
g(x) = 6x

(g - f)(3) = 6(3) - (-(3)² + 4)
(g - f)(3) = 18 - (-9 + 4)
(g - f)(3) = 18 - (-5)
(g - f)(3) = 18 + 5
(g - f)(3) = 23

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An environmental group at a local college is conducting independent tests to determine the distance a particular make of automob

melomori [17]

Answer:

$26.5265$

Step-by-step explanation:

Confidence Interval

When the population standard deviation $\sigma$ is known, the formula for a confidence interval for a population mean $\bar x$ is:

$\displaystyle \bar x \pm z\frac{\sigma}{\sqrt{n}}$

Where n is the sample size and z is the corresponding z-value from the standard normal distribution for the selected confidence level. The value of z for a 95% confidence interval is z=1.96. The rest of the values are

$\bar x=28.2,\ \sigma=2.7, \ n=10$

Calculating the confidence interval

$\displaystyle 28.2 \pm 1.96\frac{2.7}{\sqrt{10}}$

$\displaystyle 28.2 \pm 1.6735$

Or, equivalently

$26.5265$

6 0

3 years ago

Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 2.4 h, and Car B traveled the dis

Arte-miy333 [17]

One way to go about this is to first list everything we know in the form of variables. This will make it easier to see how these numbers correlate instead of trying to remember formulas to plug these numbers into.

TimeA = 2.4h (time of Car A to travel)
TimeB = 4h (time of Car B to travel)
SpeedA = SpeedB + 22mph (Speed of Car A)
SpeedB = SpeedA - 22mph (Speed of Car B)
Distance = x (the distance traveled by each car)

We are looking for SpeedA. How can we find this? Well, we know that speed multiplied by time is equal to distance, so let's start there.

SpeedA * 2.4h = x
(SpeedB + 22mph) * 2.4h = x
(2.4h * SpeedB) + 52.8miles = x

We also know that:
SpeedB * 4h = x

Since both of these equations are equal to x, we can combine them:
SpeedB * 4h = x = (2.4h * SpeedB) + 52.8miles
SpeedB * 4h = (2.4h * SpeedB) + 52.8miles
1.6h * Speed B = 52.8miles
SpeedB = 52.8/1.6 mph = 33 mph

SpeedA = SpeedB + 22mph = 33mph + 22mph = 55mph

Therefore, Car A was traveling at 55mph.

3 0

3 years ago

WHAT IS THE RELATIONSHIP BETWEEN THE ANGLE OF ELEVATION AND THE ANGLE OF DEPRESSION? GIVE AN EXAMPLE OF AN APPLICATION USING THE

Makovka662 [10]

Angles of Elevation and Depression are used in measuring heights and distances in trigonometric applications using right triangles. These angles are made when we look up or down to view objects. Devices are available to measure angles of elevation and depression. These measured angles can be used in measuring heights and distance which are either tedious or impractical to measure, by modelling the situation into right triangles

6 0

3 years ago

Read 2 more answers

Insert parentheses to make the statement true 21-8-6=7

Advocard [28]

(21-8)-6=7

and that's it

5 0

3 years ago

40x40x40+26-98+45x78x78x78 then divide by 3

kykrilka [37]

You've written "then" before 3, so i assume the real question is:

(40 * 40 * 40 + 26 - 98 + 45 * 78 * 78 * 78) / 3
Use "PEMDAS" first solve under the parenthesis, then after it.

= (64000 + 26 - 98 + 21354840) / 3
= 21418768 / 3
= 7139589.33

In short, Your Answer would be: 7139589.33

Hope this helps!

7 0

3 years ago