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algol [13]
3 years ago
10

Visualize 4.385 on a number line using magnification.

Mathematics
1 answer:
andreyandreev [35.5K]3 years ago
5 0

Answer:

Um srry I am a hack I like this app Haha I hadked this girls brainy hehehe

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PLZ HELP Simplify the rational expression. State any excluded values. 2x/-5x+x^2
Bas_tet [7]
(2x/-5x)+x^2
(x(2)/(x(-5))+x^2

(-2/5)+x^2, the x values cancel in numerator and denominator and simplify to -2/5
6 0
3 years ago
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The total price of an article is $7.02, including tax. If the tax rate is 8%, what is the retail price of the article?
masya89 [10]
Lets price of article = x
Tax  is 8%  of article = 0.08x

x+0.08x=7.02
1.08x=7.02
x=7.02/1.08 
x=6.5
The retail price is $6.50.
4 0
3 years ago
an airplane is at an altitude of 1,200 feet. It begins to ascend at a rate of 925 feet per minute. How many minutes will it take
Oksanka [162]
You start by subtracting: 16000-1200= 14800
Then you divide 14800 by how many feet the plane rises per minute 
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3 years ago
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Typing errors in a text are either nonword errors (as when "the" is typed as "teh") or word errors that result in a real but inc
nordsb [41]

Answer:

a) X is binomial with n = 10 and p = 0.3

Y is binomial with n = 10 and p = 0.7

b) The mean number of errors caught is 7.

The mean number of errors missed is 3.

c) The standard deviation of the number of errors caught is 1.4491.

The standard deviation of the number of errors missed is 1.4491.

Step-by-step explanation:

For each typing error, there are only two possible outcomes. Either it is caught, or it is not. The probability of a typing error being caught is independent of other errors. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

10 word errors.

This means that n = 10

(a) If X is the number of word errors missed, what is the distribution of X ?

Human proofreaders catch 70 % of word errors. This means that they miss 30% of errors.

So for X, p = 0.3.

The answer is:

X is binomial with n = 10 and p = 0.3.

If Y is the number of word errors caught, what is the distribution of Y ?

Human proofreaders catch 70 % of word errors.

So for Y, p = 0.7.

The answer is:

Y is binomial with n = 10 and p = 0.7

(b) What is the mean number of errors caught?

E(Y) = np = 10*0.7 = 7

The mean number of errors caught is 7.

What is the mean number of errors missed?

E(X) = np = 10*0.3 = 3

The mean number of errors missed is 3.

(c) What is the standard deviation of the number of errors caught?

\sqrt{V(Y)} = \sqrt{np(1-p)} = \sqrt{10*0.7*0.3} = 1.4491

The standard deviation of the number of errors caught is 1.4491.

What is the standard deviation of the number of errors missed?

\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{10*0.3*0.7} = 1.4491

The standard deviation of the number of errors missed is 1.4491.

6 0
3 years ago
subukin mong bigyan ng malalim at mabisang kahulugan Ang gamit Ng wika sa globalisasyon batay sa sarili mong pag unawa?​
zubka84 [21]

Answer:

#SORRY I NEED THIS ℅THANK YOU SO MUCH

#SORRY I NEED THIS Download ppt "1 1.Name the two forces that work together to keep the Earth and the moon in orbit with one another. Lesson Essential Question: How do gravity and inertia."℅THANK YOU SO MUCH

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