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Blizzard [7]
2 years ago
12

What is 24/9 in simplest form

Mathematics
2 answers:
qaws [65]2 years ago
5 0

Answer:

2 2/3

Step-by-step explanation:

hope this helps :)

don't be afraid to ask questions

DIA [1.3K]2 years ago
3 0
The answer to this question is 2 and 2/3
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A random sample of size n1= 25, taken from a normal population with a standard deviation σ1= 5, has a mean X1= 80. A second rand
sesenic [268]

Answer:

The 94% confidence interval would be given by 2.898 \leq \mu_1 -\mu_2 \leq 7.102

Step-by-step explanation:

Previous concepts  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X_1 =80 represent the sample mean 1

\bar X_2 =75 represent the sample mean 2

n1=25 represent the sample 1 size  

n2=36 represent the sample 2 size  

\sigma_1 =5 sample standard deviation for sample 1

\sigma_2 =3 sample standard deviation for sample 2

\mu_1 -\mu_2 parameter of interest.

The confidence interval for the difference of means is given by the following formula:  

(\bar X_1 -\bar X_2) \pm z_{\alpha/2}\sqrt{\frac{\sigma^2_1}{n_1}+\frac{\sigma^2_2}{n_2}} (1)  

The point of estimate for \mu_1 -\mu_2 is just given by:

\bar X_1 -\bar X_2 =80-75=5

Since the Confidence is 0.94 or 94%, the value of \alpha=0.06 and \alpha/2 =0.03, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.03,0,1)".And we see that z_{\alpha/2}=1.88  

The standard error is given by the following formula:

SE=\sqrt{\frac{\sigma^2_1}{n_1}+\frac{\sigma^2_2}{n_2}}

And replacing we have:

SE=\sqrt{\frac{5^2}{25}+\frac{3^2}{36}}=1.118

Confidence interval

Now we have everything in order to replace into formula (1):  

5-1.88\sqrt{\frac{5^2}{25}+\frac{3^2}{36}}=2.898  

5+1.8\sqrt{\frac{6^2}{36}+\frac{7^}{49}}=7.102  

So on this case the 94% confidence interval would be given by 2.898 \leq \mu_1 -\mu_2 \leq 7.102  

7 0
3 years ago
An incoming airplane is x miles due north from the control tower at an airport. A second incoming airplane is y miles due east o
MAVERICK [17]

Answer:

B. Square root

Step-by-step explanation:

using distance formula:

x = √z^2 - y^2

y = √z^2 - x^2

=> z = √x^2 + y^2

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3 years ago
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What’s the LMC of 11 and 44
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Answer:

The answer is 44.  The least common mutiple (lcm) of 11 and 44 is 44.  Please mark me brainliest! :)

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What is the area of this figure?
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Answer:

I feel like a lot of people try to get people just to do the work for them on this site.

Step-by-step explanation:

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3 years ago
Please help, this is time sensitive!!!
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<span>The approximate distance between points A and B is </span>7.62 units.
so C 
<span>

</span>
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3 years ago
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