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3 years ago

PLEASEEE HELP 25 points

Mathematics

1 answer:

Oksana_A [137]3 years ago

6 0

Answer:

slope= 1/10x and the slope represents the increase of the rental cost after x miles driven.

Step-by-step explanation:

i hope this helps :)

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SOMEBODY HELP PLSSSSS IT WOULD HELP ME ALOTT!!1

Oksi-84 [34.3K]

Would it be 5 ? i’m sorry i’m not very sure.

5 0

3 years ago

Read 2 more answers

A case of Scout cookies has 10 cartons. A carton has 12 boxes. The amount you earn on a whole case is 10(12x) dollars.

Katen [24]

Simplified expression: 120x dollars

Step-by-step explanation:

Given,

Number of cartons in case of Scout cookies = 10 cartons

Number of boxes in carton of Scout cookies = 12 boxes

Amount earned on whole case = 10(12x) dollars

To simplify the expression, we will multiply 10 by 12x

Amount earned on whole case = 120x dollars

Simplified expression: 120x dollars

Keywords: multiplication, variable

Learn more about multiplication at:

#LearnwithBrainly

8 0

3 years ago

Rebecca and Tracy are cutting strips of fabric to make a quilt. Each strip of fabric needs to be 1/3 of a foot long. They have 1

Deffense [45]

48 strips of fabric.

6 0

3 years ago

Solve for x. Round your answer to the nearest hundredth.<br> 15.56x - 200 < 758.92

jasenka [17]

Answer: x<61.63

Step-by-step explanation: Add 200 to both sides, giving you 15.56x<958.92 .

Than divide by 15.56 giving you x< x<61.627249

Round to the nearest hundredth giving you x<61.63

8 0

3 years ago

Read 2 more answers

Sketch the domain D bounded by y = x^2, y = (1/2)x^2, and y=6x. Use a change of variables with the map x = uv, y = u^2 (for u ?

cluponka [151]

Under the given transformation, the Jacobian and its determinant are

$\begin{cases}x=uv\\y=u^2\end{cases}\implies J=\begin{bmatrix}v&u\\2u&0\end{bmatrix}\implies|\det J|=2u^2$

so that

$\displaystyle\iint_D\frac{\mathrm dx\,\mathrm dy}y=\iint_{D'}\frac{2u^2}{u^2}\,\mathrm du\,\mathrm dv=2\iint_{D'}\mathrm du\,\mathrm dv$

where $D'$ is the region $D$ transformed into the $u$ - $v$ plane. The remaining integral is the twice the area of $D'$ .

Now, the integral over $D$ is

$\displaystyle\iint_D\frac{\mathrm dx\,\mathrm dy}y=\left\{\int_0^6\int_{x^2/2}^{x^2}+\int_6^{12}\int_{x^2/2}^{6x}\right\}\frac{\mathrm dx\,\mathrm dy}y$

but through the given transformation, the boundary of $D'$ is the set of equations,

$\begin{array}{l}y=x^2\implies u^2=u^2v^2\implies v^2=1\implies v=\pm1\\y=\frac{x^2}2\implies u^2=\frac{u^2v^2}2\implies v^2=2\implies v=\pm\sqrt2\\y=6x\implies u^2=6uv\implies u=6v\end{array}$

We require that $u>0$ , and the last equation tells us that we would also need $v>0$ . This means $1\le v\le\sqrt2$ and $0$ , so that the integral over $D'$ is

$\displaystyle2\iint_{D'}\mathrm du\,\mathrm dv=2\int_1^{\sqrt2}\int_0^{6v}\mathrm du\,\mathrm dv=\boxed6$

4 0

3 years ago