Which expression would be easier to simplify if you used the commutative property to change the order of the numbers?
1 answer:
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Answer:
(a), (a,c), (a,d), (a,e), (a,c,d), (a,c,e), (a,d,e), (a,c,d,e)
Step-by-step explanation:
We are given the set (a,b,c,d,e).
Total number of subsets of the above set are = 32
Subsets:
φ
(a,b,c,d,e)
(a), (b), (c), (d), (e)
(a,b), (a,c), (a,d), (a,e), (b,c), (b,d), (b,e), (c,d), (c,e), (d,e)
(a,b,c), (a,b,d), (a,b,e), (a,c,d), (a,c,e), (a,d,e), ( b,c,d), (b,c,e), (b,d,e), (c,d,e)
(a,b,c,d), (a,b,c,e), (a,b,d,e), (a,c,d,e), (b,c,d,e)
Subset having a but not b :
(a), (a,c), (a,d), (a,e), (a,c,d), (a,c,e), (a,d,e), (a,c,d,e)
Answer:
Remainder is 691.
Step-by-step explanation:
Given function is .
Now we need to find remainder if we divide given function by (x-3)
(x-3) means plug x=3 into to find remainder.
Hence remainder is 691.