First box is 100 second is 4 third is 1500 4th box is 60 and last box is 1560
Take the second equation and flip it around so the y on the left ends up on the right and the 4x on the right ends up on the left. This makes all negatives positive and all positives negative. -4x + 12 = y
Then add the first equation to the second equation
4x +12 = -7y
<u>-4x + 12 </u>=<u> y </u> this eliminates the x's
<u>24</u> = -<u> 6y</u> then divide by - 6
- 6 - 6
- 4 = y<u>
</u>So if you know that y = negative 4, you can substitute into either equation. I pick the second one because I am a lazy person.
-y + 12 = 4 x
-(-4) + 12 = 4 x combine your numbers<u>
</u> <u> 16 </u> = <u>4 x </u> then divide by 4<u>
</u> 4 = x
So your solution is: x = 4 and y = -4 or this is also written (4, -4)
Does that work for you?
Answer:
in this case, x is the amount more he needs to save per month
350=12(x+20)
distribute
350=12x+240
minus 240 both sides
110=12x
divide both sides by 12
9.166666=x
needs to save about $9.17 more per month or 29.17 permonth
Step-by-step explanation:
sorry if its wrong i tried and maybe i could get brainliest?
Move
100 to the left of a.
which makes 100a,month
IF YOU LIKE MY ANSWER PLS GIVE ME BRAINLIEST!!
Your distance from Seattle after two hours of driving at 62 mph, from a starting point 38 miles east of Seattle, will be (38 + [62 mph][2 hr] ) miles, or 162 miles (east).
Your friend will be (20 + [65 mph][2 hrs] ) miles, or 150 miles south of Seattle.
Comparing 162 miles and 150 miles, we see that you will be further from Seattle than your friend after 2 hours.
After how many hours will you and your friend be the same distance from Seattle? Equate 20 + [65 mph]t to 38 + [62 mph]t and solve the resulting equation for time, t:
20 + [65 mph]t = 38 + [62 mph]t
Subtract [62 mph]t from both sides of this equation, obtaining:
20 + [3 mph]t = 38. Then [3 mph]t = 18, and t = 6 hours.
You and your friend will be the same distance from Seattle (but in different directions) after 6 hours.
