What is the equation of the circle with center (16, - 12) and a radius of 5
1 answer:
Answer:
x^2+y^2-32x+24y+375=0
Step-by-step explanation:
Equation of circle with given centre (h,k) and radius=r is
(x-h)^2+(y-k)^2=r^2
Given centre are=(16, - 12) and radius= 5
So equation of circle=
(x-16)^2+(y- -12)^2=5^2
x^2-32x+256+y^2+24y+144=25
x^2+y^2-32x+24y+375=0
Answer
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