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ioda
3 years ago
9

What is the equation of the circle with center (16, - 12) and a radius of 5

Mathematics
1 answer:
eimsori [14]3 years ago
5 0

Answer:

x^2+y^2-32x+24y+375=0

Step-by-step explanation:

Equation of circle with given centre (h,k) and radius=r is

(x-h)^2+(y-k)^2=r^2

Given centre are=(16, - 12) and radius= 5

So equation of circle=

(x-16)^2+(y- -12)^2=5^2

x^2-32x+256+y^2+24y+144=25

x^2+y^2-32x+24y+375=0

Answer

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Answer:

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Step-by-step explanation:

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3 years ago
Fine -4A+6B (Picture provided)
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Answer:

Option a

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Step-by-step explanation:

First multiply matrix A by -4.

Then multiply the matrix B by 6.

When multiplying a matrix by a number x you must multiply each element of the matrix by x.

Then we perform operation -4A

-4\left(\begin{array}{ccc}-2&6&1\\1&9&-6\\-9&9&-9\end{array}\right)=\left(\begin{array}{ccc}8&-24&-4\\-4&-36&24\\36&-36&36\end{array}\right)

Now we perform operation 6B

6\left(\begin{array}{ccc}-5&9&6\\-2&-7&4\\1&10&-1\end{array}\right)=\left(\begin{array}{ccc}-30&54&36\\-12&-42&24\\6&60&-6\end{array}\right)

Now we add the resulting matrices

\left(\begin{array}{ccc}8&-24&-4\\-4&-36&24\\36&-36&36\end{array}\right)+\left(\begin{array}{ccc}-30&54&36\\-12&-42&24\\6&60&-6\end{array}\right)=\left(\begin{array}{ccc}-22&30&32\\-16&-78&48\\42&24&30\end{array}\right)

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4 years ago
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erma4kov [3.2K]

Answer:

5.94

Step-by-step explanation:

Multiply 2.75 by $0.76 to get $2.09

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3 years ago
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So, going back to the original expression:
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To make x positive, we will add x to both sides of the equation, thus, we get:
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