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marissa [1.9K]
3 years ago
7

HELLPP ASAP PLS, FIRST PERSON TO ANSWER CORRECTLY GETS BRAINLIEST

Mathematics
1 answer:
s2008m [1.1K]3 years ago
7 0

Answer:

Step-by-step explanation:

this may or may not be right but I tried my best

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3 years ago
The base of an open rectangular box is of length (2x+5) cm and width x cm. The area of this base is 58cm^2. The height of the op
andreev551 [17]

<u>B) </u>x   =4.28

<u>C) </u> volume =  135.25cm^3 .

<u>Step-by-step explanation:</u>

Here we have , The base of an open rectangular box is of length (2x+5) cm and width x cm. The area of this base is 58cm^2. The height of the open box is (x-2) cm. We need to find the following :

a) show that 2x^2+5x-58=0

We know that area of rectangle = length(width)

⇒ Area = length(width)

Putting values according to question we get :

⇒ 58 = (2x+5)(x)

⇒ 58 = (2x^2+5x)

⇒  2x^2+5x - 58 = 0

b) solve the equation in the question above, giving your answer to 2 decimal places

Solving this equation :

⇒  2x^2+5x - 58 = 0

By quadratic formula

⇒ x   = \frac{-b \pm \sqrt{b^2-4ac} }{2a}

⇒ x   = \frac{-5 \pm \sqrt{5^2-4(2)(-58)} }{2(2)}

⇒ x   = \frac{-5 \pm 22.11}{4}

⇒ x   = \frac{-5 + 22.11}{4} , x   = \frac{-5 - 22.11}{4}    { Since side can't be negative ! }

⇒ x   =4.28

c) calculate the volume of the box, stating units of you answer

Since x = 4.28 , other sides are

2x+5=2(4.28)+5=13.56\\x-2=4.28-2=2.28

We know that volume is given by :

⇒ length(width)(height)

⇒ 13.86(4.28)(2.28)

⇒ 135.25cm^3

Therefore , volume =  135.25cm^3 .

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