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igor_vitrenko [27]
3 years ago
13

Find the midpoint, M, of AB. А M B [?] 22

Mathematics
2 answers:
Paladinen [302]3 years ago
5 0

Answer:

M=11

Step-by-step explanation:

olya-2409 [2.1K]3 years ago
3 0

Answer:

11

Step-by-step explanation:

To find the midpoint ( or middle) we take the average of the endpoints

(A+B)/2 = (0+22)/2 = 22/2 = 11

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B. One arm extended straight to the side

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3 years ago
HELP PLEASE! Chords NO and PQ are congruent. Arc NO measures 4x + 10 and Arc PQ measures 2x + 20. What is each of their measures
Elodia [21]
4x + 10 = 2x + 20
4x - 2x = 20 - 10
2x = 10
x = 5
7 0
2 years ago
How do you work this out
oksian1 [2.3K]

Answer:

Below.

Step-by-step explanation:

To find the number of students in each grade you multiply the marks by the frequency density. The number of students is given by the area under the  rectangles.

So to find the number of students with grade U (< 160)  it is:

120 * 0.2 + 40*0.5

= 24 + 20

= 44.

The number for Grade E

= (200 - 160) * 0.5

= 40 * 0.5

= 20.

The others can be found in the same way.

6 0
4 years ago
If the sales tax in Maple Town is 9.5%, how much would an ice cream of $4.25 cost with the tax added? Please explain.
faltersainse [42]
To find the sales tax, you need to find 9.5% of 4.25

4.25*.095 = <span>.40375

Now we need to add the sales tax to the price.

4.25 + </span>.40375 = <span>4.65375
Because dollars one have 2 decimal points we should round this to 4.65

Hope this helped!
</span>
5 0
3 years ago
Read 2 more answers
How many pairs of consecutive natural numbers have a product of less than 40000? I am in 5th grade. This is supposed to be easy
Ugo [173]

Answer:

There are 199 pairs of consecutive natural numbers whose product is less than 40000.

Step-by-step explanation:

We notice that such statement can be translated into this inequation:

n \cdot (n+1) < 40000

Now we solve this inequation to the highest value of n that satisfy the inequation:

n^{2}+n < 40000

n^{2}+n -40000

The Quadratic Formula shows that roots are:

n_{1,2} = \frac{-1\pm\sqrt{1^{2}-4\cdot (1)\cdot (-40000)}}{2\cdot (1)}

n_{1,2} = -\frac{1}{2}\pm \frac{1}{2} \cdot \sqrt{160001}

n_{1} = -\frac{1}{2}+\frac{1}{2}\cdot \sqrt{160001}

n_{1} \approx 199.501

n_{2} = -\frac{1}{2}-\frac{1}{2}\cdot \sqrt{160001}

n_{2} \approx -200.501

Only the first root is valid source to determine the highest possible value of n, which is n_{max} = 199. Each natural number represents an element itself and each pair represents an element as a function of the lowest consecutive natural number. Hence, there are 199 pairs of consecutive natural numbers whose product is less than 40000.

6 0
3 years ago
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