1/2ac2 where a =5 and b=2

Mathematics

2 answers:

Evgen [1.6K]2 years ago

8 0

I’ll assume the c is b. (1/2) x (5) x (2) x (2) is 10

stiks02 [169]2 years ago

4 0

Answer: 10

Concept:

Here, we need to understand the idea of evaluation.

When encountering questions that gave you an expression with variables, then stated: "If x = a, y = b, z = c" (a, b, c are all constants), this means you should substitute the value given for each variable back to the expression.

Solve:

**Disclaimer** I assumed that the [1/2] in [1/2ac2] is a single term and [c2] in [1/2ac2] is b². If it was, then you may refer to my answer. If it was not, then you may tell me and I will redo it.

Given information

a = 5

b = 2

Given expression

(1/2) · a · b²

Substitute values into the expression

=(1/2) · (5) · (2)²

Simplify exponents

=(1/2) · (5) · (4)

Simplify by multiplication

=(2) · (5)

=10

Hope this helps!! :)

Please let me know if you have any questions

You might be interested in

For the polynomial function ƒ(x) = −x6 + 3x4 + 4x2, find the zeros. Then determine the multiplicity at each zero and state wheth

murzikaleks [220]

There is a multiple zero at 0 (which means that it touches there), and there are single zeros at -2 and 2 (which means that they cross). There is also 2 imaginary zeros at i and -i.

You can find this by factoring. Start by pulling out the greatest common factor, which in this case is -x^2.

-x^6 + 3x^4 + 4x^2

-x^2(x^4 - 3x^2 - 4)

Now we can factor the inside of the parenthesis. You do this by finding factors of the last number that add up to the middle number.

-x^2(x^4 - 3x^2 - 4)

-x^2(x^2 - 4)(x^2 + 1)

Now we can use the factors of two perfect squares rule to factor the middle parenthesis.

-x^2(x^2 - 4)(x^2 + 1)

-x^2(x - 2)(x + 2)(x^2 + 1)

We would also want to split the term in the front.

-x^2(x - 2)(x + 2)(x^2 + 1)

(x)(-x)(x - 2)(x + 2)(x^2 + 1)