Answer:
Kimberly
Step-by-step explanation:
My mother gave me the name
f(x) = 2x + 1; Paren graph = x;
The graph was shifted one unit up and stretched 2 times.
g(x) = -8(x+4) - 1 = -8x - 32 - 1 = -8x - 33
The graph was shifted 33 units down and stretched 8 times and flipped 180 degrees.
(a) Yes all six trig functions exist for this point in quadrant III. The only time you'll run into problems is when either x = 0 or y = 0, due to division by zero errors. For instance, if x = 0, then tan(t) = sin(t)/cos(t) will have cos(t) = 0, as x = cos(t). you cannot have zero in the denominator. Since neither coordinate is zero, we don't have such problems.
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(b) The following functions are positive in quadrant III:
tangent, cotangent
The following functions are negative in quadrant III
cosine, sine, secant, cosecant
A short explanation is that x = cos(t) and y = sin(t). The x and y coordinates are negative in quadrant III, so both sine and cosine are negative. Their reciprocal functions secant and cosecant are negative here as well. Combining sine and cosine to get tan = sin/cos, we see that the negatives cancel which is why tangent is positive here. Cotangent is also positive for similar reasons.
Answer:
<u>Part 1: C. $3,159.30</u>
<u>Part 2. C. –5; –135; –10,935</u>
Step-by-step explanation:
Part 1:
Price of the boat = $ 16,600
Depreciation rate = 14% = 0.14
Time of utilization of the boat = 11 years
Price of the boat after 11 years = Original price * (1 - Depreciation rate)^Time of utilization of the boat
Price of the boat after 11 years = 16,600 * (1 - 0.14)¹¹
Price of the boat after 11 years = 16,600 * 0.1903
<u>Price of the boat after 11 years = $ 3,159.30</u>
Part 2:
Let's find out the first term of the sequence given:
A(1) = -5 * 3¹⁻¹
A(1) = -5 * 1
A(1) = -5
Let's find out the fourth term of the sequence given:
A(4) = -5 * 3⁴⁻¹
A(4) = -5 * 3³
A(4) = -5 * 27
A(4) = -135
Let's find out the eighth term of the sequence given:
A(8) = -5 * 3⁸⁻¹
A(8) = -5 * 3⁷
A(8) = -5 * 2,187
A(8) = -10,935
