Answer:
wheres the question part i can't give an answer if I don't know whats its asking
Answer:
3/1
Step-by-step explanation:
Well there's 6 sides on a dice and only 2 winning numbers. 6/2=3/1. You have a good chance of losing lol. Is this what you're looking for?
~Keaura/Cendall.
Answer:
37.6 units
Step-by-step explanation:
Perimeter = sum of all sides of the triangle
To find the sum, find the distance between each points.
✔️Distance between points (-7, 6) and (5, -4):
(nearest tenth)
✔️Distance between (-7, 6) and (-7, -4):
|6 -(-4)| = 10 units
✔️Distance between (-7, -4) and (5, -4)
|-7 - 5| = 12 units
✔️ Perimeter = 15.6 + 10 + 12 = 37.6 units
Let use h= hotdogs price and c=chips price
we know that
4h +4c= 17
5h+3c=17.75
t use the elimination method we will multiply the first equation by 5 and the second one by (-4)
20h +20c=85
-20h -12c= -71
8c=14, we will divide by 8 both side and c=1.75, so a bag of potato chips cost $ 1.75
now we will substitute the c in the first equation
4h+7=17 therefore 4h=17-7, 4h=10, h=2.50
a bag of potato chips is 1.75
a hot dog costs 2.50
2
3
−
1
1
=
3
+
3
2
3
x
−
11
=
x
3
+
3
32x−11=3x+3
2
3
−
1
1
=
3
+
3
2
x
3
−
11
=
x
3
+
3
32x−11=3x+3
2
Find common denominator
2
3
−
1
1
=
3
+
3
2
x
3
−
11
=
x
3
+
3
32x−11=3x+3
2
3
+
3
(
−
1
1
)
3
=
3
+
3
2
x
3
+
3
(
−
11
)
3
=
x
3
+
3
32x+33(−11)=3x+3
3
Combine fractions with common denominator
2
3
+
3
(
−
1
1
)
3
=
3
+
3
2
x
3
+
3
(
−
11
)
3
=
x
3
+
3
32x+33(−11)=3x+3
2
+
3
(
−
1
1
)
3
=
3
+
3
2
x
+
3
(
−
11
)
3
=
x
3
+
3
32x+3(−11)=3x+3
4
Multiply the numbers
2
+
3
(
−
1
1
)
3
=
3
+
3
2
x
+
3
(
−
11
)
3
=
x
3
+
3
32x+3(−11)=3x+3
2
−
3
3
3
=
3
+
3
2
x
−
33
3
=
x
3
+
3
32x−33=3x+3
5
Find common denominator
2
−
3
3
3
=
3
+
3
2
x
−
33
3
=
x
3
+
3
32x−33=3x+3
2
−
3
3
3
=
3
+
3
⋅
3
3
2
x
−
33
3
=
x
3
+
3
⋅
3
3
32x−33=3x+33⋅3
6
Combine fractions with common denominator
2
−
3
3
3
=
3
+
3
⋅
3
3
2
x
−
33
3
=
x
3
+
3
⋅
3
3
32x−33=3x+33⋅3
2
−
3
3
3
=
+
3
⋅
3
3
2
x
−
33
3
=
x
+
3
⋅
3
3
32x−33=3x+3⋅3
7
Multiply the numbers
2
−
3
3
3
=
+
3
⋅
3
3
2
x
−
33
3
=
x
+
3
⋅
3
3
32x−33=3x+3⋅3
2
−
3
3
3
=
+
9
3
2
x
−
33
3
=
x
+
9
3
32x−33=3x+9
8
Multiply all terms by the same value to eliminate fraction denominators
2
−
3
3
3
=
+
9
3
2
x
−
33
3
=
x
+
9
3
32x−33=3x+9
3
⋅
2
−
3
3
3
=
3
(
+
9
3
)
3
⋅
2
x
−
33
3
=
3
(
x
+
9
3
)
3⋅32x−33=3(3x+9)
9
Cancel multiplied terms that are in the denominator
3
⋅
2
−
3
3
3
=
3
(
+
9
3
)
3
⋅
2
x
−
33
3
=
3
(
x
+
9
3
)
3⋅32x−33=3(3x+9)
2
−
3
3
=
+
9
2
x
−
33
=
x
+
9
2x−33=x+9
10
Add
3
3
33
33
to both sides of the equation
2
−
3
3
=
+
9
2
x
−
33
=
x
+
9
2x−33=x+9
2
−
3
3
+
3
3
=
+
9
+
3
3
2
x
−
33
+
33
=
x
+
9
+
33
2x−33+33=x+9+33
11
Simplify
Add the numbers
Add the numbers
2
=
+
4
2
2
x
=
x
+
42
2x=x+42
12
Subtract
x
x
from both sides of the equation
2
=
+
4
2
2
x
=
x
+
42
2x=x+42
2
−
=
+
4
2
−
2
x
−
x
=
x
+
42
−
x
2x−x=x+42−x
13
Simplify
Combine like terms
Multiply by 1
Combine like terms
=
4
2
x
