Answer: 
Step-by-step explanation:
Do you have answer choices?
(x,y) = (r,16)
With this knowledge, plug in r for x, and 16 for y
16 = 2(r) - 4
Isolate the r, add 4 to both sides
16 (+4) = 2r - 4 (+4)
20 = 2r
Divide 2 from both sides
20/2 = 2r/2
r = 20/2
r = 10
hope this helps
Answer:
a) 33.33%)
b) 135 minutes
c) 8.66 min
d) 50%
Step-by-step explanation:
a) the probability for a uniform distribution is
P(b<X<a) = (a-b)/(c-d) , where c and d are the maximum and minimum values
therefore the probability that the flight is more than 140 minutes ( and less than 150 since it is the maximum value)
P(140<X<150) = (a-b)/(c-d) = (150-140)/(150-120) = 10/30 = 1/3 (33.33%)
b) the mean (expected value) for a uniform probability distribution is
E(X) = (c+d)/2 = (120+150)/2 = 135 minutes
c) the standard deviation for a uniform probability distribution is
σ²(X)= (c-d)²/12 = (150-120)²/12 = 75 min²
σ = √75 min² = 8.66 min
b) following the same procedure as in a)
P(120<X<135) = (a-b)/(c-d) = (135-120)/(150-120) = 15/30 = 1/2 (50%)
Answer:
x = 1/2 y = -1/3
Step-by-step explanation:
Split it into 2 equations:
10x-9y=8
and
21y+15x=0.5
10x - 9y = 8
Step 1: Divide both sides by 10:
x = (8+9y)/(10)
Substitute x = (8+9y)/(10) into 21y+15x=0.5 :
21y + (3(8+9))/(2) = 0.5
Solve for y
<u>y= -1/3</u>
Substitute y= -1/3 into x = (8+9y)/(10)
<u>x = 1/2</u>
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