(a) We have ⌊<em>x</em>⌋ = 5 if 5 ≤ <em>x</em> < 6, and similarly ⌊<em>x</em>/3⌋ = 5 if
5 ≤ <em>x</em>/3 < 6 ==> 15 ≤ <em>x</em> < 18
(b) ⌊<em>x</em>⌋ = -2 if -2 ≤ <em>x</em> < -1, so ⌊<em>x</em>/3⌋ = -2 if
-2 ≤ <em>x</em>/3 < -1 ==> -6 ≤ <em>x</em> < -3
In general, ⌊<em>x</em>⌋ = <em>n</em> if <em>n</em> ≤ <em>x</em> < <em>n</em> + 1, where <em>n</em> is any integer.
I do not understand what is being asked in (c) and (d), so you'll have to clarify...
Answer:
2^12
Step-by-step explanation:
16^3 can be rewritten as (2^4)^3 which can then be rewritten as 2^12 by multiplying the exponents
We will not know the answer because you didn't tell us the radius or anything
Answer:
8
Step-by-step explanation:
i guessed
