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bekas [8.4K]
2 years ago
6

Determine if the data are qualitative or quantitative.

Biology
1 answer:
daser333 [38]2 years ago
4 0

Explanation:

quantitative is the answer because it's right

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How many times does the cell divide during meiosis?
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During Meiosis, Cell divides "Twice"   (2 times )

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What is a releaser? In biology
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A releaser is a stimulus from one animal to another, which causes a particular response.

Explanation:

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Why might using retroviral vectors for gene therapy increase the patient's risk of developing cancer? a. Retroviral vectors may
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The use of retroviral therapies can increase the patient's risk of developing cancer because they may integrate recombinant DNA into the genome in ways that may misregulate the expression of genes. Therefore the correct option is D.

<h3>What is retroviral therapy? </h3>

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7 0
2 years ago
Four structural domains of tRNA transcripts include the T loop, the D loop, the anticodon loop, and the
umka2103 [35]

Answer:

The correct answer will be option-B.

Explanation:

Transfer RNA or tRNA is the RNA molecule associated with the protein synthesis as it adds the specific amino acids to the nascent growing polypeptide.

The structure of the tRNA molecule resembles the shape of a clover leaf and is known as the clover leaf model. The structure contains hydrogen-bonded stems and associated loops. The stems include acceptor stem which posses CCA 3'-terminal group to attach amino acids. The anticodon loop contains an amino acid attachment site. T and D loop contains modified pseudouridine and dihydrouridine.

Thus, Option-B is the correct answer.

 

6 0
3 years ago
In chickens, having feathers on legs is dominant to having featherless legs. In a population of 200 chickens, 128 have featherle
Neporo4naja [7]

Answer:

64

Explanation:

Since the population is in Hardy-Weinberg equilibrium and the equilibrium is defined by the equation

p² + 2pq + q²

where the frequency of the homozygous dominant allele F ( feathers on the leg ) = p²,

F of homozygous ( featherless legs) = q²

F of heterogyous ( carrier of featherless allele) = 2pq

F (q²) = 128/200 = 0.64

q = √0.64 = 0.8

and p + q = 1

p = 1 - 0.8 = 0.2

2pq = 2 × 0.2 × 0.8 = 0.32

number of chickens that are heterozgous for the feathered leg allele = 0.32 × 200 = 64

3 0
3 years ago
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