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nirvana33 [79]
2 years ago
12

There are 108 flowers. 1/9 of them bloomed. How many did not bloom? How many did?

Mathematics
1 answer:
levacccp [35]2 years ago
4 0

Answer:

96 flowers did not bloom and 12 did.

Explanation:

Total flower = 108

Number of flower that bloomed

= ⅑ of the total flowers

= ⅑ of 108

= ⅑ × 108

= 108/9

= 12

So, number of flowers that did not bloom

= Total flowers - Number of flowers that bloomed

= 108 - 12

= 96

So, 96 flowers did not bloom and 12 flowers did.

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Is the triangle with side lengths of 20 mm, 24 mm,<br> and 36 mm a right triangle
adoni [48]

Answer:

no it's an acute triangle

Step-by-step explanation:

why? because any angle below 90 degrees is considered an acute triangle which in your case 20,24, and 36 are all very far from being a right triangle

7 0
3 years ago
How do I find the median​
Aleonysh [2.5K]

Answer:

ORDER THEM FROM LEAST TO GREATEST THEN CROSS OFF A NUMBER FROM EACH SIDE TILL YOU  ARE LEFT WITH ONE IN THE MIDDLE

ANSWER IS 17

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
What is differnce when there is parentheses around a number being squared?
Svetach [21]
When parentheses are around a number being squared, the output value will always be positive. 

For example: -2² vs (-2)²
-2² means the <em>negative of the square of two</em>, or -4
(-2)² means the <u /><em>square of negative two</em>, or 4

<em />
5 0
3 years ago
SOLVE FOR X<br><br> -5x + 9 = 24
boyakko [2]

Answer:

<u>x = -3</u>

Step-by-step explanation:

-5x + 9 = 24

move the nine to the other side

-5x = 15

divide

x = -3

7 0
3 years ago
A data set of 27 different numbers has a mean of 33 and a median of 33. A new data set is
Svetllana [295]

Answer:

Option D.

Step-by-step explanation:

Suppose that we have a set of N values:

{x₁, x₂, ..., xₙ}

The median is the value in the middle, and the mean is calculated as:

M = \frac{(x_1 + x_2 + x_3 ... + x_n)}{N}

Because here we have "the median" then we will assume that N is odd, and there is only one median, the value "k"  (if N was even, the median would be the mean of the two middle values, that case is really similar to the case where N is odd, so solving only one of the cases is enough)

Now we add 7 to all the values greater than the median

We subtract 7 to all values smaller than the median.

Then the median remains unchanged (because we did not add nor subtract anything to the median).

The new mean will be:

M' = \frac{(x_1 - 7) + (x_2 - 7) + ... + (x_{k}) + ... + (x_n + 7)}{N} = \frac{(x_1 + x_2 + ... + x_n) + (-7)*(n/2 - 0.5) + 7*(n/2 - 0.5)}{N}  = \frac{(x_1 + x_2 + ... + x_n)}{N} = M

So the mean does not change.

Because the mean is computed as the sum of the numbers divided by N, and the mean does not change, and N does not change, then the sum of the numbers does not change.

Finally, the standard deviation is computed as:

SD = \sqrt{\frac{(x_1 - M)^2 + ... + (xn - M)^2}{N} }

Because M does not change, if we add or subtract numbers to some of the values, the standard deviation will change (Because all the terms are squared, so the added and subtracted sevens don't cancel like in the previous cases)

Then the only value that does not have the same value in both the original and new data sets is the standard deviation.

6 0
3 years ago
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