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Alina [70]
2 years ago
11

Convert 123 into quinary number .​

Mathematics
1 answer:
muminat2 years ago
5 0

<em>To convert decimal number 1</em><em>2</em><em>3</em><em> to quinary, follow these steps:</em>

<em>1</em><em>.</em><em> </em><em>Divide 1</em><em>2</em><em>3</em><em> </em><em>by 5 keeping notice of the quotient and the remainder.</em>

<em>2</em><em>.</em><em>Continue dividing the quotient by 5 until you get a quotient of zero.</em>

<em>3</em><em>.</em><em> </em><em>Then just write out the remainders in the reverse order to get quinary equivalent of decimal number 1</em><em>2</em><em>3</em><em>.</em>

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kolbaska11 [484]
Yes, because if you divide 4 and 3 by 2, you get 2 and 1.5
5 0
2 years ago
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D) Vivek is 30 years younger than his father. After 10 years their ages will be in the ratio 1:2. Find their present ages.​
tangare [24]

Answer:

I think Vivek is 20 and his father is 50

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6 0
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Which graph best represents the equation x2 + (y – 1)2 = 3?
Harman [31]

Answer:

Step-by-step explanation:

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6 0
2 years ago
Write a polynomial of degree 5 with zero x=0,i square root 7, -2i
professor190 [17]

Answer:

P(x)=x^5+11x^3+28x

Step-by-step explanation:

<u>Roots of a polynomial</u>

If we know the roots of a polynomial, say x1,x2,x3,...,xn, we can construct the polynomial using the formula

P(x)=a(x-x_1)(x-x_2)(x-x_3)...(x-x_n)

Where a is an arbitrary constant.

We know three of the roots of the degree-5 polynomial are:

x_1=0;\ x_2=\sqrt{7}\boldsymbol{i}:\ x_3=-2\boldsymbol{i}

We can complete the two remaining roots by knowing the complex roots in a polynomial with real coefficients, always come paired with their conjugates. This means that the fourth and fifth roots are:

x_4=-\sqrt{7}\boldsymbol{i}:\ x_3=+2\boldsymbol{i}

Let's build up the polynomial, assuming a=1:

P(x)=(x-0)(x-\sqrt{7}\boldsymbol{i})(x+\sqrt{7}\boldsymbol{i})(x-2\boldsymbol{i})(x+2\boldsymbol{i})

Since:

(a+b\boldsymbol{i})\cdot (a-b\boldsymbol{i})=a^2+b^2

P(x)=(x)(x^2+7)(x^2+4)

Operating the last two factors:

P(x)=(x)(x^4+11x^2+28)

Operating, we have the required polynomial:

\boxed{P(x)=x^5+11x^3+28x}

7 0
2 years ago
50 pts for this!!!
butalik [34]
Length
maximum: 24m
minimum: 0.1m

width
maximum: 17.2
minimum:0.1 

thats all I got sorry.
8 0
2 years ago
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