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3 years ago

Lynn paid $12.21 for ribbon. The cost per yard was $1.48.

Mathematics

2 answers:

just olya [345]3 years ago

7 0

Answer:

Step-by-step explanation:

All we need to do is divide the values we are given.

12.21 / 1.48 = 8.25

Best of Luck!

dusya [7]3 years ago

4 0

The answer is d; 8.25 yards

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A baby gains about 2 1/5 pounds each month for the first three months after birth.when he was 3 months old,tyler weighed 14 1/10

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const2013 [10]

Answer:

240

Step-by-step explanation:

240 + 60 = 300 you can tell this by realising that ratio to have 4x one over the other would be 20 per 100, using this rate 3x, 240 and 60

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A quality analyst of a tennis racquet manufacturing plant investigates if the length of a junior's tennis racquet conforms to th

Burka [1]

Answer:

Confidence interval : $21.506$ to $24.493$

Step-by-step explanation:

A quality analyst selects twenty racquets and obtains the following lengths:

21, 25, 23, 22, 24, 21, 25, 21, 23, 26, 21, 24, 22, 24, 23, 21, 21, 26, 23, 24

So, sample size = n =20

Now we are supposed to find Construct a 99.9% confidence interval for the mean length of all the junior's tennis racquets manufactured at this plant.

Since n < 30

So we will use t-distribution

Confidence level = 99.9%

Significance level = α = 0.001

Now calculate the sample mean

X=21, 25, 23, 22, 24, 21, 25, 21, 23, 26, 21, 24, 22, 24, 23, 21, 21, 26, 23, 24

Sample mean = $\bar{x}=\frac{\sum x}{n}$

Sample mean = $\bar{x}=\frac{21+25+23+22+24+21+25+21+23+ 26+ 21+24+22+ 24+23+21+ 21+ 26+23+ 24}{20}$

Sample mean = $\bar{x}=23$

Sample standard deviation = $\sqrt{\frac{\sum(x-\bar{x})^2}{n-1}}$

Sample standard deviation = $\sqrt{\frac{(21-23)^2+(25-23)^2+(23-23)^2+(22-23)^2+(24-23)^2+(21-23)^2+(25-23)^2+(21-23)^2+(23-23)^2+(26-23)^2+(21-23)^2+(24-23)^2+(22-23)^2+(24-23)^2+(23-23)^2+(21-23)^2+(21-23)^2+(26-23)^2+(23-23)^2+(24-23)^2}{20-1}}$

Sample standard deviation= s = $1.72$

Degree of freedom = n-1 = 20-1 -19

Critical value of t using the t-distribution table $t_{\frac{\alpha}{2}$ = 3.883

Formula of confidence interval : $\bar{x} \pm t_{\frac{\alpha}{2}} \times \frac{s}{\sqrt{n}}$

Substitute the values in the formula

Confidence interval : $23 \pm 1.73 \times \frac{1.72}{\sqrt{20}}$

Confidence interval : $23 -3.883 \times \frac{1.72}{\sqrt{20}}$ to $23 + 3.883 \times \frac{1.72}{\sqrt{20}}$

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Create a list of steps, in order, that will solve the following equation.

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Answer:

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Solve for a:

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Grouping like terms, 2 a - 1 + 10 = 2 a + (10 - 1):

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10 - 1 = 9:

2 a + 9 = 3

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Subtract 9 from both sides:

2 a + (9 - 9) = 3 - 9

Hint: | Look for the difference of two identical terms.

9 - 9 = 0:

2 a = 3 - 9

Hint: | Evaluate 3 - 9.

3 - 9 = -6:

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(2 a)/2 = (-6)/2

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