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3 years ago

The product of 4 and the difference between 8 and 3 wrote as an expression

Mathematics

2 answers:

masha68 [24]3 years ago

5 0

Answer:

4(8-3)

Remember to use PEMDAS if you have to solve :)

Paul [167]3 years ago

4 0

Answer:

4(8-3)

hope this helps :)

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This relationship is not a function. Choose the sentence or

IRINA_888 [86]

Answer:

The input x = 1 has many outputs.

The graph is a vertical line.

Step-by-step explanation:

Hi there!

A function is defined as a relation that only gives one output for every given input. For every x-value, there is only one y-value.

Because the x-value of 1 gives us an infinite number of y-values, this is therefore not a function.

More generally, no vertical line is a function for this reason.

I hope this helps!

8 0

2 years ago

Plz help me I will give you a brainest

Lady bird [3.3K]

Answer: −2.4f − 22

Step-by-step explanation: simply combine like terms. -2.7f + .3f would be -2.4f, and -14 - 8 is -22.

4 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%7B9x%7D%5E%7B2%7D%20-%20%7B%28x%7D%5E%7B2%7D%20-%204%29%20%7B%7D%5E%7B2%7D%20

Alenkinab [10]

Answer:

${ x^2+3x-4}$

Step-by-step explanation:

Factor top and bottom.

The numerator is a difference of two squares, and the denominator is a quadratic.

$\frac{ {9x}^{2} - {(x}^{2} - 4)^{2} }{4 + 3x - {x}^{2} }$

= $\frac{ (3x+x^2-4)(3x-x^2+4) }{(1+x)(4-x)}$

= $\frac{ (x-1)(x+4) (1+x)(4-x) }{(1+x)(4-x)}$

If x does not equal -1 and does not equal 4, we can cancel the common factors in italics to give

= ${ (x-1)(x+4)}$

= ${ x^2+3x-4}$

3 0

3 years ago

Read 2 more answers

Solve the equation, and check the solution. 1/3s =1/5

Vaselesa [24]

Answer:

3/5

Step-by-step explanation:

1/3s=1/5

s=(1/5)/(1/3)

s=(1/5)(3/1)

s=3/5

7 0

4 years ago

Read 2 more answers

A new screening test for Lyme disease is developed for use in the general population. The sensitivity and specificity of the new

Anit [1.1K]

Answer:

predictive value of a positive test = 18.18%

predictive value of a negative test = 94.03%

Step-by-step explanation:

Sensitivity = 60% = 0.6

Specificity = 70% = 0.7

Let True Positive = TP

True Negative = TN

False Negative = FN

$Sensitivity = \frac{TP}{TP + FN} \\0.6 = \frac{TP}{TP + FN} \\0.6TP + 0.6FN = TP\\0.4TP = 0.6FN\\TP = 1.5 FN$

$Specificity = \frac{TN}{TN + FP} \\0.7 = \frac{TN}{TN + FP} \\0.7TN + 0.7FP = TN\\0.7FP = 0.3 TN\\TN = 7/3 FP$

Prevalence = 10% = 0.1

Three hundred people are screened, $T_{total} = 300$

Total number of people having the disease, $T_{disease} = ?$

$Prevalence = \frac{T_{disease} }{T_{total} } \\0.1 = \frac{T_{disease} }{300 }\\T_{disease} = 30$

$T_{disease} = TP + FN\\30 = TP + FN$

But TP = 1.5 FN

30 = 1.5 FN + FN

30 = 2.5 FN

FN = 30/2.5

FN = 12

TP = 1.5 FN = 1.5 * 12

TP = 18

$FP + TN = T_{total} - T_{disease} \\FP + TN = 300 - 30\\FP + TN = 270\\FP + \frac{7}{3} FP = 270\\\frac{10}{3} FP = 270\\FP = 27 * 3\\FP = 81$

81 + TN = 270

TN = 189

To calculate the Predictive value of positive test (PPT)

$PPT = \frac{TP}{TP + FP} * 100\\PPT = \frac{18}{18+81} * 100\\PPT = \frac{18}{99} * 100\\PPT = 18.18 \%$

To calculate the Predictive value of negative test (PNT)

$PPT = \frac{TN}{FN + TN} * 100\\PPT = \frac{189}{189+12} * 100\\PPT = \frac{189}{201} * 100\\PPT = 94.03 \%$

7 0

3 years ago