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dedylja [7]
2 years ago
11

18) Solve the system. 0.4x - 0.1y = 2 0.2x + 0.5y = 1 A) (5, 0) B) (0, 5) C) (-5, 0) Eliminate D) (3, -10) please help me its ex

am time
Mathematics
2 answers:
Artemon [7]2 years ago
6 0
To solve the set of equations given above, we can use the substitution method where we substitute one equation to the other and solving for one variable. We do as follows:

<span>0.4x - 0.1y = 2
x = 5 + 0.25y

0.2x + 0.5y = 1
</span>0.2(5 + 0.25y)+ 0.5y = 1
y = 0
x = 5

Therefore, the correct answer from the choices is option A, (5,0).
Olenka [21]2 years ago
3 0

Answer: A 5,0


Step-by-step explanation:


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Jon ate too many holiday cookies and gained 2.2 kilograms in December. Then he went on a diet and lost 1.5 kilograms in January.
gogolik [260]

Answer:

Jon lost a total of 3 kilograms in these 3 months.

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Weight that Jon gained in December = 2.2 kilograms

Weight that Jon lost in January = 1.5 kilograms

Weight that Jon lost in February = 3.7 kilograms

Overall Change in his weight = Total Weight he gained - Total weight he Lost

Total weight he gained is 2.2 kilograms as he only gained weight in December. Total weight he lost will be sum of weights he lost in January and February.

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Total change in Jon's Weight = 2.2 - 5.2 = -3.0 kilograms

This shows that Jon lost a total of 3 kilograms in these 3 months.

Conclusion:

The statement that best describe the total change in his weight is: Jon lost a total of 3 kilograms in these 3 months

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Read 2 more answers
The number of accidents per week at a hazardous intersection varies with mean 2.2 and standard deviation 1.1. This distribution
cluponka [151]

Answer:

Step-by-step explanation:

Hello!

The definition of the Central Limi Theorem states that:

Be a population with probability function f(X;μ,δ²) from which a random sample of size n is selected. Then the distribution of the sample mean tends to the normal distribution with mean μ and variance δ²/n when the sample size tends to infinity.

As a rule, a sample of size greater than or equal to 30 is considered sufficient to apply the theorem and use the approximation.

X[bar]≈N(μ;σ²/n)

If the variable of interest is X: the number of accidents per week at a hazardous intersection.

There is no information about the distribution of this variable, but a sample of n= 52 weeks was taken, and since the sample is large enough you can approximate the distribution of the sample mean to normal. With population mean μ= 2.2 and standard deviation σ/√n= 1.1/√52= 0.15

I hope it helps!

5 0
2 years ago
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