X^2 + x + 1 + 3x^2 + 3x + 2. Just combine the like terms:
x^2 + 3x^2 + x + 3x + 1 + 2
4x^2 + 4x + 3. <--- the sum.
Answer:
what is it?
Step-by-step explanation:
what's your question
Answer:
d = 14/5
Step-by-step explanation:
The point (-4,2) means that;
At x = -4, y = 2
Now general form of a linear equation is;
Ax + By + C = 0
We are given;
4y = 3x + 6
Rearranging to the form of a linear equation gives;
3x - 4y + 6 = 0
Thus, A = 3, B = -4 and C = 6
Thus, at point (-4,2), distance between them is;
d = (3(-4) - 4(2) + 6)/√(3² + (-4)²)
d = -14/5
We will take the absolute value.
Thus; d = 14/5
Answer: only (x-y=4) and (x+y=4).
Step-by-step explanation:
Notice target point has y=0, so all terms with y are zero. Then all 6 equations reduce to m x = k, for various m and k. So calculate 4×m and compare to k six times.
x - y = 4 4=4 yes
-x - y = 4 -4=4 no
2x - y = 7 8=7 no
x + y = 4 4=4 yes
2x + y = 7 8=7 no
2x + y = -7 8=-7 no.
