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mihalych1998 [28]
3 years ago
12

Solve for b.

Mathematics
2 answers:
Dvinal [7]3 years ago
8 0
Expression: <span>a = 9b²c

b</span>² = a/9c

b = √(a/9c)

b = √a/3√c
Or b = 1/3 √(a/c)

In short, Your Answer would be: Option D

Hope this helps!
Ipatiy [6.2K]3 years ago
3 0

Answer:

b=\pm\frac{1}{3}\sqrt{\frac{a}{c}}

Step-by-step explanation:

Given expression a=9b^2c

We have to find the value in terms of b

Consider the given expression a=9b^2c

Divide both side by c, we have

\frac{a}{c}=9b^2

Again divide by 9 , we have

\frac{a}{9c}=b^2

Taking square root both side, we have,

\sqrt{\frac{a}{9c}}=\sqrt{b^2}

Simplify , we have,

\sqrt{\frac{a}{9c}}=b

We know \sqrt{9}=\pm 3

Thus, b=\pm\frac{1}{3}\sqrt{\frac{a}{c}}

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B. 4.5=2m+g
f. 9.25=3m+2g

1.25=m

sub

b. 4.5=2(1.25)+g
f. 9.25=3(1.25)+2g

b. 4.5=2.5+g
f. 9.25=3.75+2g

minus 2.5 from both sides on the b. equaion and minus 3.75 from both sides on the f. equation

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f. 5.5=2g

divide both sides of f. equation by 2

b. 2=g
f. 2.75=g

2.75-2=0.75
finn paied $0.75 more for a bag of grapes
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4 years ago
Star Cellular has several phone plans to choose from. The $39 monthly service plan allows 500 anytime minutes and charges 40 cen
dlinn [17]
A) $59.00

50 x .40 + 29 = 59
4 0
3 years ago
Need step-by-step. Please answer correctly. This determines what grade I get. I will mark brainliest to the first person who ans
tatyana61 [14]

Answer:

  3√3

Step-by-step explanation:

For the problem shown here, your answer 3√3 is correct.

When there is a radical by itself in the denominator, you multiply numerator and denominator by a radical that results in the product being rational. For a square root, that will usually be the same square root:

  \dfrac{9}{\sqrt{3}}=\dfrac{9}{\sqrt{3}}\cdot\dfrac{\sqrt{3}}{\sqrt{3}}=\dfrac{9\sqrt{3}}{3}=\boxed{3\sqrt{3}}

__

If the problem has a sum in the denominator involving a square root, then you multiply numerator and denominator by the conjugate of that sum (the sum with the sign changed). This uses the special product "difference of squares" to eliminate the radical term.

<u>Example</u>:

  \dfrac{9}{2-\sqrt{3}}=\dfrac{9}{2-\sqrt{3}}\cdot\dfrac{2+\sqrt{3}}{2+\sqrt{3}}=\dfrac{9(2+\sqrt{3})}{2^2-(\sqrt{3})^2}=\dfrac{18+9\sqrt{3}}{4-3}\\\\=\boxed{18+9\sqrt{3}}

__

It is easy to demonstrate that none of the offered choices for this problem has the same value as 9/√3.

9/√3 ≈ 5.196. Offered choices have values of about 4.798, 1.732, 6.681, 23.196 -- none even close.

Please discuss this question with your teacher.

3 0
3 years ago
I need help with this question! Will mark brainliest :)
irinina [24]

Answer:

hiii

your answer is option d

<h2><em>HOPE IT HELPS YOU OUT PLEASE MARK IT AS BRAINLIEST AND FOLLOW ME PROMISE YOU TO FOLLOW BACK ON BRAINLY.IN</em></h2>
3 0
3 years ago
Read 2 more answers
Rewrite each equation in standard form. <br><br> 4 and 5 only
nekit [7.7K]

Answer:

4) 2=4x-3y

5) 51=21x-3y

Step-by-step explanation:

I gave it my best shot, I used fraction busters to cancel out the fractions and then I used simple math and distributive property. Hope it helps.

7 0
2 years ago
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