Answer:
B 20
Step-by-step explanation:
Answer:
Rearrange the equations that result from use of the Pythagorean theorem.
Step-by-step explanation:
Transversal AB crossing parallel lines AD and BC makes supplementary interior same-side angles A and B. Since A = 90°, B must be 90°. The Pythagorean theorem then applies in the right triangles ABC and ABD.
We can use that theorem to write two expressions for AB^2:
BD^2 -AD^2 = AB^2 = AC^2 -BC^2
The middle expression, AB^2, isn't needed beyond this point. Adding (AD^2 -AC^2) to both sides of the equation gives the desired result:
BD^2 -AC^2 = AD^2 -BC^2
Let 3<em>n</em> + 1 denote the "number" in question. The claim is that
(3<em>n</em> + 1)² = 3<em>m</em> + 1
for some integer <em>m</em>.
Now,
(3<em>n</em> + 1)² = (3<em>n</em>)² + 2 (3<em>n</em>) + 1²
… = 9<em>n</em>² + 6<em>n</em> + 1
… = 3<em>n</em> (3<em>n</em> + 2) + 1
… = 3<em>m</em> + 1
where we take <em>m</em> = <em>n</em> (3<em>n</em> + 2).
Answer:
2
Step-by-step explanation:
2×4+5-3=
8+5-3=10
10/5=2
f(x) + g(x) = 3x³ + 8x - 24
that is 3x³ + 7x - 26 + x + 2 = 3x³ + 8x - 24
