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crimeas [40]
2 years ago
11

Angelique travels 75 miles. Jamila travels 115 kilometres. Show that Angelique has travelled futher than Jamila.

Mathematics
1 answer:
jasenka [17]2 years ago
8 0

Answer:

Step-by-step explanation:

-we know :

we must have the <u>same unit</u> on the distance traveled in order to be able to compare distances  

1 mile = 1.6 kilometers

-Angelique traveled 75 miles ( 120 kilometers)

75 miles = 1.6 *75 = 120 kilometers

-Jamila traveled 115 kilometers  is given in the problem

-Angelique has travelled further than Jamila because

120 kilometers > 115 kilometers

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What is the following quotient? 5/√11-√3
kati45 [8]

ANSWER

\frac{5( \sqrt{11}  +  \sqrt{3} )} {8}

EXPLANATION

The given rational function is

\frac{5}{ \sqrt{11} -  \sqrt{3}}

We need to rationalize the denominator by multiplying both the numerator and the denominator by the conjugate of

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which is

\sqrt{11}   +  \sqrt{3}

When we rationalize we obtain:

\frac{5( \sqrt{11}  +  \sqrt{3} )}{(\sqrt{11}  - \sqrt{3} )( \sqrt{11}  +  \sqrt{3} )}

The denominator is now a difference of two squares:

(a - b)(a + b) =  {a}^{2}  -  {b}^{2}

We apply this property to get

\frac{5( \sqrt{11}  +  \sqrt{3} )}{( \sqrt{11}) ^{2}    -  ( \sqrt{3}) ^{2}  )}

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This simplifies to

\frac{5( \sqrt{11}  +  \sqrt{3} )} {8}

Or

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