Let's solve your equation step-by-step.<span><span>100−<span>6x</span></span>=<span>160−<span>10x</span></span></span>Step 1: Simplify both sides of the equation.<span><span>100−<span>6x</span></span>=<span>160−<span>10x</span></span></span><span>Simplify: (Show steps)</span><span><span><span>−<span>6x</span></span>+100</span>=<span><span>−<span>10x</span></span>+160</span></span>Step 2: Add 10x to both sides.<span><span><span><span>−<span>6x</span></span>+100</span>+<span>10x</span></span>=<span><span><span>−<span>10x</span></span>+160</span>+<span>10x</span></span></span><span><span><span>4x</span>+100</span>=160</span>Step 3: Subtract 100 from both sides.<span><span><span><span>4x</span>+100</span>−100</span>=<span>160−100</span></span><span><span>4x</span>=60</span>Step 4: Divide both sides by 4.<span><span><span>4x</span>4</span>=<span>604</span></span><span>x=15</span>Answer:<span>x=<span>15
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Answer:
z ≤ 1/3
Step-by-step explanation:
3z - 3 ≤ -2 Add 3
3z ≤ 1 Divide by 3
z ≤ 1/3
6.5x2.5=16.25
0.6x2.5=1.5
6.0x2.5=15
1.) 1.5
2.) 15
3.) 16.25
I hope that helped. Good luck!
Answer:
{x ∈ ℝ : x ≥ π/6 +2πn and x ≤ π/6 + 2πn and n ∈ ℤ}
Step-by-step explanation:
sinx can run from -1 to +1
2sinx can run from -2 to +2
2sinx -1 can run from -3 to +1
However, the square root is imaginary when x < 0. So, the condition is
2sinx -1 ≥ 0
2sinx ≥ 1
sinx ≥ ½
x ≥ π/6 (30°)
So, in the interval [0, 2π], π/6 ≤ x ≤ 5π/6
However, the sine is a cyclic function and repeats itself every 2π.
Over all real numbers, the condition is (π/6 +2πn) ≤ x ≤ (5π/6 + 2πn).
The domain is then
{x ∈ ℝ : x ≥ π/6 +2πn and x ≤ π/6 + 2πn and n ∈ ℤ}
22 squared + 120 squared
14484
rad 14484 equals 122
the answer is b
