Congruent sides have congruent angles so
w=70
Triangle angles =180 so
70+70+x=180
140+x=180
-140 both sides
x=40
supplimentary angles (angles that make up a line) =180 so
w+y=180
70+y=180
-70 both sides
y=110
triangle angles =180 so
110+25+z= 180
135+z=180
-135 both sides
z=45
w=70
x=40
y=110
z=45
25 - 4x = 15 - 2x + 10
-10 - 10
15 - 4x = 15 - 2x
-15 -15
-4x = - 2x
no solution
I'm assuming the limit is supposed to be
Multiply the numerator by its conjugate, and do the same with the denominator:
so that in the limit, we have
Factorize the first term in the denominator as
The 
terms cancel, leaving you with
and the limand is continuous at 
, so we can substitute it to find the limit has a value of -1/18.
If 2m and 8m are the base and height of the parallelogram, then the area is 16.
the answer of this question is 603.2yd2
