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3 years ago

1/9 x² + 2/3 xy +y² ∴

Mathematics

1 answer:

Karo-lina-s [1.5K]3 years ago

6 0

Answer:

Here is your ans. hope this helps you.

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Answer:3!

Step-by-step explanation:

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3 years ago

The table gives an inequality and a number to multiply both sides of the inequality by. Identify the new, true inequality.

zepelin [54]

Multiplying both sides of an inequality by a negative number reverses the inequality symbol.

<h3>How to determine the true inequalities?</h3>

The table of values is given as:

A: (-16 > -4) (-16 < -4) (-16 = -4)

B: (40 > 8) (40 < 8) (40 = 8

C: (-45 > 15) (-45 < 15) (-45 =15)

D: (35 > -20) (35 < -20) (35 = -20)

In the above list of inequalities, the true inequalities are

-16 < -4 --- because -16 is less than -4

40 > 8 --- because 40 is greater than 8

-45 < 15 --- because -45 is less than 15

35 > -20 --- because 35 is greater than -20

Lastly, when an inequality is multiplied or divided by a negative number, the inequality sign changes

Read more about inequality at:

brainly.com/question/17675534

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2 years ago

The population of a community is known to increase at a rate proportional to the number of people present at time t. The initial

qaws [65]

Answer:

Step-by-step explanation:

Let P be the population of the community

So the population of a community increase at a rate proportional to the number of people present at a time

That is

$\frac{dp}{dt} \propto p\\\\\frac{dp}{dt} =kp\\\\ [k \texttt {is constant}]\\\\\frac{dp}{dt} -kp =0$

Solve this equation we get

$p(t)=p_0e^{kt}---(1)$

where p is the present population

p₀ is the initial population

If the initial population as doubled in 5 years

that is time t = 5 years

We get

$2p_o=p_oe^{5k}\\\\e^{5k}=2$

Apply In on both side to get

$Ine^{5k}=In2\\\\5k=In2\\\\k=\frac{In2}{5} \\\\\therefore k=\frac{In2}{5}$

Substitute $k=\frac{In2}{5}$ in $p(t)=p_oe^{kt}$ to get

$\large \boxed {p(t)=p_oe^{\frac{In2}{5}t }}$

Given that population of a community is 9000 at 3 years

substitute t = 3 in ${p(t)=p_oe^{\frac{In2}{5}t }}$

$p(3)=p_oe^{3 (\frac{In2}{5}) }\\\\9000=p_oe^{3 (\frac{In2}{5}) }\\\\p_o=\frac{9000}{e^{3(\frac{In2}{5} )}} \\\\=5937.8$

<h3>Therefore, the initial population is 5937.8</h3>

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3 years ago

24 foot wire is tied from a stake in the ground to the top of flagpole. If the angle elevation from the stake to the top of the

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3 years ago

Which of the following functions is graphed below ?(:

dlinn [17]

y = |x+3| - 4

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4 years ago

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