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never [62]
3 years ago
9

1. What is the basic economic problem that societies must solve?

Mathematics
1 answer:
Gnesinka [82]3 years ago
5 0

Answers

Step-by-step explanation:

1.D

2.A

3. A

4. B

5. B

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Vikki [24]

Answer:

Step-by-step explanation:

I am sorry but what is the question

6 0
3 years ago
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What will go Inside the boxes?
e-lub [12.9K]

Answer:

18500 is the initial value

Every year they increase by a factor of 1.03

Step-by-step explanation:

This is written in the form

y = ab^x  where a is the initial value and b is the growth rate/decrease

y = (18500) (1.03)^t

The initial value is 18500

The students will increase by 1.03 - 1 = .03

The factor of increase is what they multiply by which is 1.03

8 0
3 years ago
Upon what does the force of gravity between two objects depend? The amount of attraction between the two objects A
soldier1979 [14.2K]

Answer: D

Step-by-step explanation: i did the exam.

7 0
3 years ago
Consider the triangle below.
Pepsi [2]

The measure of angle P is 29 degrees

The sum of an interior angle of a triangle is 180 degrees. Given the following parameters:

  • m<M = 15x + 5
  • m<N = 3x + 2
  • m<P = 5x - 11

Taking the sum and equating to 180 degrees:

m<M + m<N + m<P = 180 degrees

15x + 5 + 3x + 2 + 5x - 11 = 180

23x - 4 = 180

23x = 184

x = 184/23

x = 8

Get the measure of m<P

m<P = 5x - 11

m<P = 5(8) - 11

m<P = 40 - 11

m<P = 29 degrees

Hence the measure of angle P is 29 degrees

Learn more on angles here: brainly.com/question/25770607

7 0
2 years ago
Sandra throws an object straight up into the air with initial velocity of 38 ft per square from platform that is 30 ft above the
expeople1 [14]

Answer:

3 seconds.

Step-by-step explanation:

We have been given that Sandra throws an object straight up into the air with initial velocity of 38 ft per second from platform that is 30 ft above the ground.

To find the time it will take for object to hit the ground, we will use formula:  

h(t)=-16t^2+v_0t+h_0, where, v_0 represents initial velocity and h_0 represents initial height.

Upon substituting our given initial velocity and initial height, we will get:

h(t)=-16t^2+38t+30

We know that object will hit the ground, when height will be 0, so we will equate object's height equal to 0 and solve for t as:

-16t^2+38t+30=0

Divide by 2:

-8t^2+19t+15=0

Upon using quadratic formula, we will get:

t=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{-19\pm\sqrt{19^2-4(-8)(15)}}{2(-8)}

t=\frac{-19\pm\sqrt{361+480}}{-16}=\frac{-19\pm\sqrt{841}}{-16}

t=\frac{-19\pm29}{-16}

t=\frac{-19-29}{-16},t=\frac{-19+29}{-16}

t=\frac{-48}{-16},t=\frac{10}{-16}

t=3,t=-\frac{5}{8}

Since time cannot be negative, therefore, it will take 3 seconds for object to hit the ground.

7 0
3 years ago
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