By applying Pythagorean's theorem, the missing side of this right-angled triangle is: A. 7√3 inches.
<h3>How to find the missing side?</h3>
By critically observing the triangle shown in the image attached below, we can logically deduce that it is a right-angled triangle. Thus, we would find the missing side by applying Pythagorean's theorem:
z² = x² + y²
Also, the sides of this right-angled triangle are:
- Opposite side = x inches.
- Adjacent side = 7 inches.
Substituting the given parameters into the formula, we have;
14² = x² + 7²
196 = x² + 49
x² = 196 - 49
x² = 147
x = √147
x = √49 × √3
x = 7√3 inches.
Read more on Pythagorean theorem here: brainly.com/question/23200848
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Answer:
21
Step-by-step explanation:
Let n represent the number we're looking for. Then ...
n × (proteus length) = 3 × (palustris length)
n × 0.7 mm = 3 × 4.9 mm
n = (3 × 4.9 mm)/(0.7 mm) = 3 × 49/7 = 3 × 7
n = 21
You would have to line up 21 amoeba proteus to equal the length of three pelomyxa palustris.
Answer:
x=12
Step-by-step explanation:
7+5=12
brainliest?
Answer:
- (6-u)/(2+u)
- 8/(u+2) -1
- -u/(u+2) +6/(u+2)
Step-by-step explanation:
There are a few ways you can write the equivalent of this.
1) Distribute the minus sign. The starting numerator is -(u-6). After you distribute the minus sign, you get -u+6. You can leave it like that, so that your equivalent form is ...
(-u+6)/(u+2)
Or, you can rearrange the terms so the leading coefficient is positive:
(6 -u)/(u +2)
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2) You can perform the division and express the result as a quotient and a remainder. Once again, you can choose to make the leading coefficient positive or not.
-(u -6)/(u +2) = (-(u +2)-8)/(u +2) = -(u+2)/(u+2) +8/(u+2) = -1 + 8/(u+2)
or
8/(u+2) -1
Of course, anywhere along the chain of equal signs the expressions are equivalent.
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3) You can separate the numerator terms, expressing each over the denominator:
(-u +6)/(u+2) = -u/(u+2) +6/(u+2)
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4) You can also multiply numerator and denominator by some constant, say 3:
-(3u -18)/(3u +6)
You could do the same thing with a variable, as long as you restrict the variable to be non-zero. Or, you could use a non-zero expression, such as 1+x^2:
(1+x^2)(6 -u)/((1+x^2)(u+2))
