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3 years ago

8

It shows the equations but it is a little confusing I don't want to get the problem wrong please help me out. Ill give you brain

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1 answer:

Viktor [21]3 years ago

6 0

Answer:εδΑΒΓΒΕ

$U4\leq \sqrt{x} \sqrt[n]{x} 64$

Step-by-step explanation:

73hsay is a little bit too long and ∩679∨78ω8㏒∴≠÷±

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I need help with this math problem!!

Vesnalui [34]

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3 years ago

Use graph to answer the question

Vesna [10]

Answer: $36.86^{\circ}$

Step-by-step explanation:

Given

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3 years ago

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Alexxandr [17]

The answer is b 3,5,9

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3 years ago

The price of a technology stock was

inna [77]

9.82-9.71=.11

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3 years ago

Solve for x<br><img src="https://tex.z-dn.net/?f=0%20%3D%20%20-%20%7B%20e%20%7D%5E%7B%20-%20x%7D%20%20%2B%203%20%7Be%7D%5E%7B3x%

Brilliant_brown [7]

$\bf \textit{Logarithm Cancellation Rules} \\\\ \stackrel{\stackrel{\textit{we'll use this one}}{\downarrow }}{log_a a^x = x}\qquad \qquad a^{log_a x}=x~\hfill\stackrel{recall}{ln=log_e}\qquad log_e(e^z)=z \\\\[-0.35em] \rule{34em}{0.25pt}$

$\bf 0=-e^{-x}+3e^{3x}\implies e^{-x}=3e^{3x}\implies \cfrac{1}{e^x}=3e^{3x}\implies 1=e^x\cdot 3e^{3x} \\\\\\ 1=3e^xe^{3x}\implies \cfrac{1}{3}=e^{x+3x}\implies \cfrac{1}{3}=e^{4x}\implies ln\left( \cfrac{1}{3} \right)=ln\left( e^{4x} \right) \\\\\\ ln\left( \cfrac{1}{3} \right)=4x\implies \cfrac{ln\left( \frac{1}{3} \right)}{4}=x$

and you plug that in your calculator to get about -0.27465307216702742285.

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3 years ago