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2 years ago

What is the answer to this problem

Mathematics

2 answers:

7nadin3 [17]2 years ago

4 0

Answer:

5 have a dog. 6 dont have a dog. 5 dont have a cat.

Step-by-step explanation:

koban [17]2 years ago

3 0

U have both a dog and a cat

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Can someone help me ASAP!!! Please!!!!

g100num [7]

Answer:

step 1. Angle bisector theorem.

step 2. 14/6 = 21/ (3x - 12)

step 3. 14(3x - 12) =21(6)

step 4. 6x - 24 = 18

step 5. 6x = 42

step 6. x = 7.

7 0

2 years ago

A triangular pyramid has these dimensions.

marishachu [46]

Answer: 42 cm3

Step-by-step explanation:

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2 years ago

A researcher does a study on knowledge of animals in cat lovers compared to dog lovers. In actuality, dog lovers have a greater

suter [353]

Answer:

This decision is not statistically significant .

Step-by-step explanation:

Hypothesis testing is set up so that you can prove a null hypothesis. Therefore, when you do not find evidence against the null hypothesis, you fail to reject the null hypothesis or the result is not statistically significant.

6 0

2 years ago

I need help with #15

gladu [14]

15. MP(5,11) S(3,5) M(x,y)

(3+x)/2 = 5 x=7

(5+y)/2 =-11 y=-27

M(7,-27) is the other point

8 0

3 years ago

Consider a system with one component that is subject to failure, and suppose that we have 115 copies of the component. Suppose f

castortr0y [4]

Answer:

Step-by-step explanation:

From the given information:

the mean $(\mu) = 115 \times 20$

= 2300

Standard deviation = $20 \times \sqrt{115}$

Standard deviation (SD) = 214.4761

TO find:

a) $P(x > 3500)= P(Z > \dfrac{3500-\mu}{214.4761})$

$P(x > 3500)= P(Z > \dfrac{3500-2300}{214.4761})$

$P(x > 3500)= P(Z > \dfrac{1200}{214.4761})$

$P(x > 3500)= P(Z >5.595)$

From the Z-table, since 5.595 is > 3.999

$P(x > 3500)=1-0.9999$

P(x > 3500) = 0.0001

Here, the replacement time for the mean $(\mu) = \dfrac{0+0.5}{2}$

= 0.25

Replacement time for the Standard deviation $\sigma = \dfrac{0.5-0}{\sqrt{12}}$

$\sigma = 0.1443$

For 115 component, the mean time = (115 × 20)+(114×0.25)

= 2300 + 28.5

= 2328.5

Standard deviation = $\sqrt{(115\times 20^2) +(114\times (0.1443)^2)}$

= $\sqrt{(115\times 400) +(114\times 0.02082249}$

= $\sqrt{(46000) +2.37376386}$

= $\sqrt{(46000) +(2.37376386)}$

= $\sqrt{46002.374}$

= 214.482

Now; the required probability:

$P(x > 4125) = P(Z > \dfrac{4125- 2328.5}{214.482})$

$P(x > 4125) = P(Z > \dfrac{1796.5}{214.482})$

$P(x > 4125) = P(Z >8.376)$

$P(x > 4125) =1- P(Z$

From the Z-table, since 8.376 is > 3.999

P(x > 4125) = 1 - 0.9999

P(x > 4125) = 0.0001

7 0

1 year ago