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2 years ago

9

The longer base of an isosceles trapezoid measures 23 ft. The nonparallel sides measure 9 ft, and the base angles measure 80°. F

ind the length of a diagonal.

1 answer:

Snowcat [4.5K]2 years ago

3 0

Answer:

Hi,

Step-by-step explanation:

Using Al's kashi theorem,

diag²=9²+23²-2*9*23*cos(80°)=538,109654....

diag=23,197190... (ft)

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The number of girls in cobbs class is 2 less than 3 times the number of boys. She has 26 students in her class how many are boys

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Answer:

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Step-by-step explanation:

Make a system of equations where g is for girls and b is for boys.

b+g=26

g=3b-2

Substitute "3b-2" in for "g" in the first equation.

b+(3b-2)=26

Rewrite without the parentheses because it's addition and not multiplication.

b+3b-2=26

Combine like terms.

4b-2=26

Add 2 to both sides.

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Solution:

Given function $h(t)=-16t^2+15t+6.5$

To find the value of h(t) when $t=\frac{15}{32}$ :

$h(t)=-16t^2+15t+6.5$

Substitute $t=\frac{15}{32}$ in the given function.

$$h\left(\frac{15}{32} \right)=-16\left(\frac{15}{32} \right)^2+15\left(\frac{15}{32} \right)+6.5$

$$=-16\left(\frac{225}{1024} \right)+15\left(\frac{15}{32} \right)+6.5$

Now multiply the common terms into inside the bracket.

$$=-\left(\frac{3600}{1024} \right)+\left(\frac{225}{32} \right)+6.5$

Now, in the first term, the numerator and denominator both have common factor 16. So reduce the first term into the lowest term.

$$=-\left(\frac{225}{64} \right)+\left(\frac{225}{32} \right)+6.5$

To make the denominator same, take LCM of the denominators.

LCM of 64 and 32 = 64

$$=-\left(\frac{225}{64} \right)+\left(\frac{225\times2}{32\times2} \right)+6.5\times\frac{64}{64}$

$$=-\frac{225}{64} +\frac{450}{64}+\frac{416}{64}$

$$=\frac{-225+450+416}{64}$

$$=\frac{641}{64}$

= 10.02

$$h\left(\frac{15}{32} \right)=10.02$

Hence the value of h(t) when $t=\frac{15}{32}$ is 10.02.

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