A circle of radius 1 is inscribed within a square. What is the probability that a randomly-selected point with the square is also within the circle?
Step-by-step explanation:
HOPE ITS HELP
Combine like terms
c+5.3=0.6
Subtract 5.3 from both sides
c=-4.7
Answer:
Hi there!
Your answer is:
<em>8</em><em>.</em><em>6</em><em> </em><em>units</em>
Step-by-step explanation:
The distance formula is
√ ( (x2-x1)^2 + (y2-y1)^2 )
In your points:
A (-3, -2)
-3 is x1
-2 is y1
B (4, -7)
4 is x2
-7 is y2
Plug in to distance formula
√ ( 4-( -3))^2 + ( -7 - (-2))^2
√ (4+3)^2 + (-7+2)^2
√ (7^2) + ( -5)^2
√ 49 + 25
√ 74
This equals roughly 8.6 units!
Answer:
23x = -115
Step-by-step explanation:
In the substitution method, you must solve for 1 variable in 1 equation to replace it in the other equation. For the system:
2x - 7y = 4
3x + y = -17
Solving for y in the second equation:
y = -17 - 3x
Replacing y in the first equation:
2x - 7(-17 - 3x) = 4
2x + 119 + 21x = 4
23x = -115
This is the new equation after use the substitution method.
Answer:
No, equivalent quarterly rate will be approx 1.75%
Step-by-step explanation:
Given that Chan deposited money into his retirement account that is compounded annually at an interest rate of 7%.
We know that there are 4 quarters in 1 year.
So to find that equivalent quarterly we will divide given yearly rate by number of quarters.
That means divide 7% by 4.
which gives 1.75%.
But that is different than Chan's though of 2% quarterly interest.
Hence Chan is wrong.
