A prime number between 10 and 20 is 13 because if u divide 26 by 2 u get 13
Answer: it is -1
Step-by-step explanation: rate of change can be defined as Δy/Δx, or the change in y over the change in c (commonly referred to as rise over run). By looking at the numbers we can see that the relationship modeled is linear (has a constant rate of change), so we are able to use this formula to calculate its rate of change. Simply calculate the change between any two values of y and (the associated) values of x and divide them to obtain your solution. I’m not the best at explaining math in words so here is the solution represented symbolically:
Rate of change = Δy/Δx
Δy/Δx = (y2-y1)/(x2-x1)
(y2-y1)/(x2-x1) = (1 - (-2))/(2 - 5) //the selected values for y2,y1,x2, and x1 are the last and first values for each, respectively.
3/-3 = -1
Answer:
Step-by-step explanation:
Given
One-eighth times three-elevenths
Required
Solve
One-eighth means 1/8
Three-elevenths means 3/11
So, mathematically; the above expression is represented as thus:
To solve this, we simply multiply the numerator and the denominator together.
After multiplying these together, the next is to check if the resulting can be simplified
If yes,we simplify it and if otherwise, we live it like that.
So,
At this point, the fraction can't be simplified any further.
Hence,
Answer:
I believe 4, but I might be wrong.
Step-by-step explanation:
If you look, it's going down -4 every time. So that means if you're going up, it's going +4 after you skip a space. So, skip, then 0, then skip, and that's 4.
Answer:
D. ![xy\sqrt[3]{9y}](https://tex.z-dn.net/?f=xy%5Csqrt%5B3%5D%7B9y%7D)
Step-by-step explanation:
![\sqrt[3]{9x^3y^4}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B9x%5E3y%5E4%7D)
![\sqrt[3]{9}\sqrt[3]{x^3}\sqrt[3]{y^4}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B9%7D%5Csqrt%5B3%5D%7Bx%5E3%7D%5Csqrt%5B3%5D%7By%5E4%7D)
The ![\sqrt[3]{x^3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E3%7D)
cancels out to become x:
![\sqrt[3]{9}x\sqrt[3]{y^4}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B9%7Dx%5Csqrt%5B3%5D%7By%5E4%7D)
Split the 
![\sqrt[3]{9}x\sqrt[3]{y^3}\sqrt[3]{y^1}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B9%7Dx%5Csqrt%5B3%5D%7By%5E3%7D%5Csqrt%5B3%5D%7By%5E1%7D)
![\sqrt[3]{y^3} =y](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7By%5E3%7D%20%3Dy)
![xy\sqrt[3]{9} \sqrt[3]{y}](https://tex.z-dn.net/?f=xy%5Csqrt%5B3%5D%7B9%7D%20%5Csqrt%5B3%5D%7By%7D)
Put the cube root of y and cube root of 9 together:
