21,300 bc 813* 5=4,065 *25=101,625 *4=106,500 /5= 21,300
Answer:
<h2>See the explanation.</h2>
Step-by-step explanation:
Sin2α = 2SinαCosα.
Cos2α = (Cosα)^2 - (Sinα)^2.
Sin4α can be written as Sin2(2α).
Similarly Cos4α can be written as Cos2(2α).
![Sin 4\alpha = 2Sin 2\alpha \times Cos 2\alpha = 2Sin 2\alpha \times(Cos^{2} \alpha - Sin^{2} \alpha ) = 4Sin \alpha \times Cos \alpha \times (Cos^{2} \alpha - Sin^{2} \alpha )](https://tex.z-dn.net/?f=Sin%204%5Calpha%20%3D%202Sin%202%5Calpha%20%5Ctimes%20Cos%202%5Calpha%20%3D%202Sin%202%5Calpha%20%5Ctimes%28Cos%5E%7B2%7D%20%5Calpha%20-%20Sin%5E%7B2%7D%20%5Calpha%20%29%20%3D%204Sin%20%5Calpha%20%5Ctimes%20Cos%20%5Calpha%20%5Ctimes%20%28Cos%5E%7B2%7D%20%5Calpha%20-%20Sin%5E%7B2%7D%20%5Calpha%20%29)
It is given that tanα=3.
Sinα(Sinα) =
[
], the values either be both positive or both negative, as the value of tanα is positive only on first and third quadrant.
Sin4α =
.
Cos4α = ![Cos^{2} 2\alpha - Sin^{2} 2\alpha = (Cos^{2} \alpha - Sin^{2} \alpha )^{2} - Sin^2 {2\alpha } = (Cos^{2} \alpha - Sin^{2} \alpha )^{2} - (2Sin \alpha Cos \alpha )^{2} = (-\frac{8}{10} )^{2} - \frac{4\times9}{100} = \frac{64 - 36}{100} = \frac{28}{100} = \frac{7}{25}](https://tex.z-dn.net/?f=Cos%5E%7B2%7D%202%5Calpha%20%20-%20Sin%5E%7B2%7D%202%5Calpha%20%3D%20%28Cos%5E%7B2%7D%20%5Calpha%20-%20Sin%5E%7B2%7D%20%5Calpha%20%29%5E%7B2%7D%20-%20Sin%5E2%20%7B2%5Calpha%20%7D%20%3D%20%28Cos%5E%7B2%7D%20%5Calpha%20-%20Sin%5E%7B2%7D%20%5Calpha%20%29%5E%7B2%7D%20-%20%282Sin%20%5Calpha%20Cos%20%5Calpha%20%29%5E%7B2%7D%20%3D%20%28-%5Cfrac%7B8%7D%7B10%7D%20%29%5E%7B2%7D%20-%20%5Cfrac%7B4%5Ctimes9%7D%7B100%7D%20%3D%20%5Cfrac%7B64%20-%2036%7D%7B100%7D%20%3D%20%5Cfrac%7B28%7D%7B100%7D%20%3D%20%5Cfrac%7B7%7D%7B25%7D)
Answer:
12 people
Step-by-step explanation:
i know u are using mathswatch i feel your pain but however hard you try you will almost never get the right show your working out
Answer:
1/4
Step-by-step explanation:
If theres 20 students total in the class and 3/4 went to the field trip meaning 3 groups of 5 that means 5 students remain in class
1 feet = 0.3048 m
23 feet = x meter
23×0.3048 = 7.0104 m