Question

for the line segment whose end points are A (0,0) and B (4,3) , find the x coordinate for the point located 2/3 the distance from A to B

Answer 1

Answer:

2.7

Step-by-step explanation:

2/3 * 4 (the distance between 0 and 4) = 2.6666667 aka 2.7

after you get that number, you add it to the first x coordinate, which is 0. 0+2.7= 2.7

Answer 2

The coordinates of x are (1.6, 1.2).

Solution:

Given points of the line segment are A(0, 0) and B(4, 3)

X be the point divided the line segment AB in the distance $\frac{2}{3}$.

i.e., in the ratio of 2 : 3.

Section formula:

$P(x, y)=\left(\frac{m x_{2}+nx_{1}}{m+n}, \frac{my_{2}+n y_{1}}{m+n}\right)$

Here, $x_1=0, y_1=0, x_2=4,y_2=3$ and m = 2, n = 3

Substitute these in the section formula,

$X(x, y)=\left(\frac{2\times4+3\times0}{2+3}, \frac{2\times3+3\times0}{2+3}\right)$

           $=\left(\frac{8+0}{5}, \frac{6+0}{5}\right)$

           $=\left(\frac{8}{5}, \frac{6}{5}\right)$

X(x, y) = (1.6, 1.2)            

The coordinates of x are (1.6, 1.2).