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miss Akunina [59]
2 years ago
5

3.Find the area of Triangle and Parallelogram having base 13.5cm and height is 18cm.​

Mathematics
1 answer:
patriot [66]2 years ago
3 0
  • Base=13.5cm
  • Height=18cm

\\ \sf\longmapsto Area=\dfrac{1}{2}Base\times Height

\\ \sf\longmapsto Area=\dfrac{1}{2}(18)(13.5)

\\ \sf\longmapsto Area=9(13.5)

\\ \sf\longmapsto Area=121.5cm^2

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Step-by-step explanation:

Step 1: Write out limit

\lim_{x \to 2} (x+1)(3x^2-9)

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hoa [83]

Answer:

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Step-by-step explanation:

Given function:

h(t)=-6t^2+24t

where:

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Rewrite in the form h(t)=a(t-h)^2+k

The quickest way to do this is to expand h(t)=a(t-h)^2+k and compare coefficients with the original function.

\begin{aligned}h(t)& =a(t-h)^2+k\\ & = at^2-2aht+ah^2+k\end{aligned}

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\begin{aligned}\implies at^2& =-6t^2\\ a &=-6\end{aligned}

\begin{aligned}\implies -2aht & =24t\\ -2(-6)ht& =24t\\ 12ht & = 24t\\ 12h & = 24\\ h & = 2\end{aligned}

\begin{aligned}\implies ah^2+k & = 0\\(-6)(2)^2+k &=0\\ -24+k & =0\\ k &=24 \end{aligned}

Therefore, substituting the found values into the equation:

h(t)=-6(t-2)^2+24

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the equation shown however is a polynomial.</span>
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