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Elenna [48]
2 years ago
7

(w + 4)(w2 + 3 w-6) find the product.

Mathematics
2 answers:
vladimir2022 [97]2 years ago
5 0

Answer:

w^3 + 7w^2 + 6w - 24

<em>Brainliest, please!</em>

Step-by-step explanation:

(w + 4)(w^2 + 3w - 6)

w^3 + 3w^2 - 6w + 4w^2 + 12w - 24

w^3 + 7w^2 + 6w - 24

GrogVix [38]2 years ago
4 0

Answer:

6w+2

Step-by-step explanation:

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Question 9 (10 points)<br> Solve for x,<br> 2(x - 1) + 4 = 4(x + 1)
Nutka1998 [239]
1. Expand
2x − 2 + 4 = 4x + 4

2. Simply
2x + 2 = 4x + 4

3. Subtract
2 = 4x + 4 - 2x

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5.Subtract
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Use the following graph to solve the equation 3n + 7 = 52
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8 0
2 years ago
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(y - 2)2 = y2 – 6y + 4<br> Is this statement true or false?
trasher [3.6K]
<h3>Answer: False</h3>

==============================================

Explanation:

I'm assuming you meant to type out

(y-2)^2 = y^2-6y+4

This equation is not true for all real numbers because the left hand side expands out like so

(y-2)^2

(y-2)(y-2)

x(y-2) .... let x = y-2

xy-2x

y(x)-2(x)

y(y-2)-2(y-2) ... replace x with y-2

y^2-2y-2y+4

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So if the claim was (y-2)^2 = y^2-4y+4, then the claim would be true. However, the right hand side we're given doesn't match up with y^2-4y+4

--------------------------

Another approach is to pick some y value such as y = 2 to find that

(y-2)^2 = y^2-6y+4

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0 = -4

We get a false statement. This is one counterexample showing the given equation is not true for all values of y.

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3 years ago
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