The common factors for 20 is 1,5
25 is 1,5
40 is 1,5
GCF:5
For the first 6 1/3
second is 14/25
third 2 29/42
2x + 3y = 630
x + y = 245 then you want to get rid of x so in the second equation × by -2 and get -2x -2y =-490 subtract this equation from the first to get y=$140 substitute 140 in for y and get x= $105 and 2x=210 and 3y=420 210 +420=630
Answer:
0.01
Step-by-step explanation:
Y and X is y
The coding of the statistic is used to make it easier to work with the large sunshine data set
- The mean of the sunshine is 3.05
![\overline 6](https://tex.z-dn.net/?f=%5Coverline%206)
- The standard deviation is approximately <u>18.184</u>
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Reason:
The given parameters are;
The sample size, n = 3.
∑x = 947
Sample corrected sum of squares, Sₓₓ = 33,065.37
The mean and standard deviation = Required
Solution:
![Mean, \ \overline x = \dfrac{\sum x_i}{n}](https://tex.z-dn.net/?f=Mean%2C%20%5C%20%5Coverline%20x%20%3D%20%5Cdfrac%7B%5Csum%20x_i%7D%7Bn%7D)
The mean of the daily total sunshine is therefore;
![Mean, \ \overline x = \dfrac{947}{30} \approx 31.5 \overline 6](https://tex.z-dn.net/?f=Mean%2C%20%5C%20%5Coverline%20x%20%3D%20%5Cdfrac%7B947%7D%7B30%7D%20%5Capprox%2031.5%20%5Coverline%206)
![s = \dfrac{x}{10 } - \dfrac{1}{10}](https://tex.z-dn.net/?f=s%20%3D%20%5Cdfrac%7Bx%7D%7B10%20%7D%20-%20%5Cdfrac%7B1%7D%7B10%7D)
![E(s) = \dfrac{31.5 \overline 6}{10 } - \dfrac{1}{10} = 3.05 \overline 6](https://tex.z-dn.net/?f=E%28s%29%20%3D%20%5Cdfrac%7B31.5%20%5Coverline%206%7D%7B10%20%7D%20-%20%5Cdfrac%7B1%7D%7B10%7D%20%3D%203.05%20%5Coverline%206)
- The mean ≈ 3.05
![\overline 6](https://tex.z-dn.net/?f=%5Coverline%206)
Alternatively
,![The \ mean \ of \ the \ daily \ total \ sunshine, \, s = \dfrac{31.5 \overline 6 - 1}{10 } = 3.05\overline 6](https://tex.z-dn.net/?f=The%20%5C%20mean%20%5C%20%20of%20%5C%20%20the%20%5C%20%20daily%20%20%5C%20total%20%20%5C%20sunshine%2C%20%20%5C%2C%20s%20%3D%20%5Cdfrac%7B31.5%20%5Coverline%206%20-%201%7D%7B10%20%7D%20%3D%203.05%5Coverline%206)
The mean of the daily total sunshine,
≈3.05![\overline 6](https://tex.z-dn.net/?f=%5Coverline%206)
![Var(s) = \left(\dfrac{1}{10}\right)^2 \times Var \left(x \right)](https://tex.z-dn.net/?f=Var%28s%29%20%3D%20%5Cleft%28%5Cdfrac%7B1%7D%7B10%7D%5Cright%29%5E2%20%5Ctimes%20Var%20%5Cleft%28x%20%5Cright%29)
Therefore;
![Var(s) = \left(\dfrac{1}{10}\right)^2 \times 33,065.37 = 330,6537](https://tex.z-dn.net/?f=Var%28s%29%20%3D%20%5Cleft%28%5Cdfrac%7B1%7D%7B10%7D%5Cright%29%5E2%20%5Ctimes%2033%2C065.37%20%3D%20330%2C6537)
Therefore;
The standard deviation,
≈ <u>18.184</u>
Learn more about coding of statistic data here:
brainly.com/question/14837870